CODEWITHSUNDEEP
c
Tigger12
Tigger12

Reputation: 53

Converting Hex To Ascii Memory Access

So I have a memory block that is fill with hex values, and I want to read in those hex values as Ascii. Unfortunately, I can't seem to figure out how to do this.

char* charstring = malloc(sizeof(uint16_t));
uint8_t test = 0x65;
sprintf(charstring, "%x ", test);
fprintf(Output, "%s", charstring);
free(charstring);

This just gives me a ton of "65", not the "e" I was expecting. I know it's a simple question, but I've literally clicked every link on the front page of google and can't figure out my problem!

Upvotes: 0

Views: 162

Answers (1)

Yu Hao
Yu Hao

Reputation: 122403

You get 65 because you are using %x as the format specifier, change it to %c for the character value.

Note that you don't have enough space for charstring for the null terminator. Fix it.

Upvotes: 5

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