Reputation: 2032
I have used the gii tool to create crud application. I have 3 tables the tbl_targetcities, lib_cities, and lib_provinces. I was able to connect lib_cities to tbl_targetciteis but not the lib_provinces. And also the sorting of city / Municipality does not work. It seems that it sorts according ti the ID.
tbl_target_cities
lib_cities
lib_provinces
sample View
So far here is my relation in the model.
public function getCityName()
{
return $this->hasOne(LibCities::className(),['city_code'=>'city_code']);
}
in my view file...
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
[
'attribute'=>'city_code',
'value'=>'cityName.city_name'
],
[
'attribute'=>'prov code',
'value'=>'cityName.city_name'
],
'kc_classification',
'cluster',
'grouping',
'priority',
'launch_year',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
How to display the prov_name from lib_provinces???
EDIT to answer user2839376 question in the comment box
IN THE SEARCH MODEL CLASS
$query = TblSpBub::find();
$query->joinWith('brgyCode')->joinWith(['cityCode'])->joinWith(['cityCode.provCode']);
$covered= LibAreas::find()->where(['user_id'=>yii::$app->user->identity->id])->all();
$query->all();
$dataProvider = new ActiveDataProvider([
'query' => $query,
'sort'=> ['defaultOrder' => ['id'=>SORT_DESC]],
]);
$dataProvider->sort->attributes['city'] = [
'asc' => ['lib_Cities.city_name' => SORT_ASC],
'desc' => ['lib_Cities.city_name' => SORT_DESC],
];
$dataProvider->sort->attributes['province'] = [
'asc' => ['lib_provinces.prov_name' => SORT_ASC],
'desc' => ['lib_provinces.prov_name' => SORT_DESC],
];
Upvotes: 2
Views: 3052
Reputation: 511
Done it, Heres how.
in addition to the above code (original post)
// in Model I added an additional function
public function getTaskowner()
{
return $this->hasOne(Tasks::className(), ['id' => 'task_id'])
->with(
['location','taskowner']
);
}
and in view i did this
....
'columns' => [
....
[
'class' => 'kartik\grid\DataColumn',
'value'=> 'tasks.location.taskowner.name',
.....
],
.....
and it worked
key points. used an array with the 'with->(..)' to include both then in the view added 'tasks.location.taskowner.name', to join them all
Upvotes: 0
Reputation: 4611
In LibCities
model add new relation:
public function getProvince()
{
return $this->hasOne(LibProvince::className(),['prov_code'=>'prov_code']);
}
And change getCityName
relation. You should add with()
for relation:
public function getCityName()
{
return $this->hasOne(LibCities::className(),['city_code'=>'city_code'])->with(['province']);
}
And in view correct your columnto this:
[
'attribute'=>'prov code',
'value'=>'cityName.province.prov_name'
],
Upvotes: 7
Reputation: 545
You have to use the function relations() in models.
In tbl_target_cities model:
public function relations()
{
return array(
'city' => array(self::HAS_ONE, 'LibCities', 'city_code'),
);
}
In LibCities model :
public function relations()
{
return array(
'province' => array(self::HAS_ONE, 'LibProvinces', 'prov_code'),
'targets' => array(self::HAS_MANY, 'TargetCity', 'city_code',
);
}
This will allowed you to jump throw the LibCities model, now you can simply acces to prov name like this :
$model->city->province->prov name;
Note : You need to have the 3 models defined.
EDIT
array(
'name' => 'province name',
'value' => $data->city->province->prov_name;
),
Upvotes: 0