CODEWITHSUNDEEP
cif-statement
Jacob
Jacob

Reputation: 91

C programming issue

I've created a simple guessing game. Pick a number between 0 and 100, depending on the number you enter the program will output hot, Warm, Cold or correct!. The number I've chosen to be the correct answer is 51. My program compiles and runs but always outputs correct! for every value I enter. Thanks for helping if you decide to.

    int main(void)

{
    int number, answer;
    answer = 51;

    printf("Enter a number between 0 and 100:\n");
    scanf("%d", &number);

    if ((number > 51) && (number <= 56) || (number < 51) && (number >= 46))
    {
            printf("Hot\n");
    }     
    else if ((number > 56) && (number <= 66) || (number < 46) && (number >= 36))
    {
            printf("Warm\n");
    }
    else if ((number > 66) && (number <= 100) || (number <36) && (number >= 0))
    {
            printf("Cold\n");
    }
    else if ((number > 100) || (number < 0))
    {
            printf("Error number has to be between 0 and 100 - re run\n");
    } 
    else (number = 51);
    {
            printf("Correct!\n");
    } 
    system ("pause");
    return 0;    
}

Upvotes: 0

Views: 85

Answers (5)

paxdiablo
paxdiablo

Reputation: 882596

This little snippet:

else (number = 51);
{
    printf("Correct!\n");
}

is actually equivalent to:

else
    (number = 51);
//=======================
{
    printf("Correct!\n");
}

The first part of that is the else clause which, if activated, will set number to 51.

The second part is totally disconnected from the if statement section and is a standalone block that will execute no matter what.

If you must put the condition there for readability (and it would be == rather than =), you could do:

else // (number == 51)
{
    printf("Correct!\n");
}

As an aside, you could make your code shorter and more readable by starting at the specific and moving to the general, something like (just replacing the if statement):

if (number == 51)
    printf ("Correct!\n");
else if ((number >= 46) && (number <= 56))
    printf ("Hot\n");
else if ((number >= 36) && (number <= 66))
    printf ("Warm\n");
else if ((number >= 0) && (number <= 100))
    printf ("Cold\n");
else
    printf ("Error,  number has to be between 0 and 100 - re run\n");
}

You don't need to ever check the two ranges (above and below) for "temperature" since the inner ranges have already been checked.

Upvotes: 4

Fish2B
Fish2B

Reputation: 1

In the last else statement, you should either use else if (number == 51) { ... } or

else 
{
    ...
}

Upvotes: 0

mARK bLOORE
mARK bLOORE

Reputation: 176

your code says: if none of the if statements is satisfied, assign 51 to number. and then always print "Correct!\n".

Upvotes: 0

Gopi
Gopi

Reputation: 19874

else (number = 51);
{
   printf("Correct!\n");
}

can be re-written as

else 
{
   number = 51;
}
{
   printf("Correct!\n");
}

So irrespective of what your number is the printf("Correct!\n"); gets executed.

It can be fixed like

else
{
   printf("Correct!\n");
}

Upvotes: 1

odbhut.shei.chhele
odbhut.shei.chhele

Reputation: 6264

remove the condition from the else statement.

int main(void)

{
    int number, answer;
    answer = 51;

printf("Enter a number between 0 and 100:\n");
scanf("%d", &number);

if ((number > 51) && (number <= 56) || (number < 51) && (number >= 46))
{
        printf("Hot\n");
}     
else if ((number > 56) && (number <= 66) || (number < 46) && (number >= 36))
{
        printf("Warm\n");
}
else if ((number > 66) && (number <= 100) || (number <36) && (number >= 0))
{
        printf("Cold\n");
}
else if ((number > 100) || (number < 0))
{
        printf("Error number has to be between 0 and 100 - re run\n");
} 
else
{
        printf("Correct!\n");
}
return 0;

}

Upvotes: 0

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