Reputation: 5694
I have a data frame like this:
df
VALUE ABS_CALL DETECTION P-VALUE
1007_s_at "957.729231881542" "P" "0.00486279317241156"
1053_at "320.632701283368" "P" "0.0313356324173416"
117_at "429.842323161046" "P" "0.0170004527476119"
121_at "2395.7364289242" "P" "0.0114473584876183"
1255_g_at "116.493632746934" "A" "0.39799368200131"
1294_at "739.927122116896" "A" "0.0668649772942343"
I want to convert the row names into the first column. Currently I use something like this to make row names as the first column:
d <- df
names <- rownames(d)
rownames(d) <- NULL
data <- cbind(names,d)
Is there a single line to do this?
Upvotes: 242
Views: 470549
Reputation: 78842
Or you can use tibble
's rownames_to_column
which does the same thing as David's answer:
library(tibble)
df <- tibble::rownames_to_column(df, "VALUE")
Note: The earlier function called add_rownames()
has been deprecated and is being replaced by tibble::rownames_to_column()
Upvotes: 253
Reputation: 131
df = data.frame(columnNameILike = row.names(df), df, row.names=NULL)
Upvotes: 4
Reputation: 79
data <- data %>%
rownames_to_column(var="the name you want")
Upvotes: 7
Reputation: 4070
dplyr::as_tibble(df, rownames = "your_row_name")
will give you even simpler result.
Upvotes: 9
Reputation: 5694
Or by using DBI
s sqlRownamesToColumn
library(DBI)
sqlRownamesToColumn(df)
Upvotes: 3
Reputation: 3822
Moved my comment into an answer per suggestion above:
You don't need extra packages, here's a one-liner:
d <- cbind(rownames(d), data.frame(d, row.names=NULL))
Upvotes: 37
Reputation: 92300
You can both remove row names and convert them to a column by reference (without reallocating memory using ->
) using setDT
and its keep.rownames = TRUE
argument from the data.table
package
library(data.table)
setDT(df, keep.rownames = TRUE)[]
# rn VALUE ABS_CALL DETECTION P.VALUE
# 1: 1 1007_s_at 957.7292 P 0.004862793
# 2: 2 1053_at 320.6327 P 0.031335632
# 3: 3 117_at 429.8423 P 0.017000453
# 4: 4 121_at 2395.7364 P 0.011447358
# 5: 5 1255_g_at 116.4936 A 0.397993682
# 6: 6 1294_at 739.9271 A 0.066864977
As mentioned by @snoram, you can give the new column any name you want, e.g. setDT(df, keep.rownames = "newname")
would add "newname" as the rows column.
Upvotes: 168
Reputation: 537
Alternatively, you can create a new dataframe (or overwrite the current one, as the example below) so you do not need to use of any external package. However this way may not be efficient with huge dataframes.
df <- data.frame(names = row.names(df), df)
Upvotes: 41