CODEWITHSUNDEEP
bashshellunix
Endika
Endika

Reputation: 357

Executing script containing variables

Inside an script we are executing another script in the same directory which contain some variables definition:

SCRIPT1:

cd $configDir
script=PLS00170.sh
./config_fecha$script.sh

if [ ! -f /f_PL_50007622_Hist_Rel_Sico_Vta_Cp.$F1S4_FEOPERACA1 ]

config_fechaPLS00170.sh.sh:

#! /bin/ksh
#------------------------------------
#FEOPERAC
#------------------------------------
F1S4_FEOPERACA1=20150401
....

The Script 1 is not able to resolve the script $F1S4_FEOPERACA1:

Sysout:

...
+ ./config_fechaPLS00170.sh.sh
+ [ ! -f /f_PL_50007622_Hist_Rel_Sico_Vta_Cp. ]
...

Any idea?

Upvotes: 0

Views: 40

Answers (1)

Bart van Heukelom
Bart van Heukelom

Reputation: 44094

You're executing the second script in its own process, so any variables defined there will be lost when it exits.

You could instead "source" the second script into the first one. This will run it as if the text was literally there. You can do that with

. ./config_fechaPLS00170.sh.sh    # note the first dot, then a space

or

source ./config_fechaPLS00170.sh.sh

Upvotes: 3

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