CODEWITHSUNDEEP
djangohtmlcombobox
clement l
clement l

Reputation: 109

Displaying a combobox for a OneToOneField

I would like to show a combobox with a OneToOneField:

models.py:

class Aliment(models.Model):
    id = models.AutoField(primary_key=True)
    name = models.CharField(max_length=200)
    type_aliment_id = models.OneToOneField(type_aliment)
    mesurande_id = models.OneToOneField(mesurande)
    calories = models.IntegerField(default=0)
    proteines = models.IntegerField(default=0)

class type_aliment(models.Model):
    id = models.AutoField(primary_key=True)
    name = models.CharField(max_length=200)

forms.py:

class AlimentForm(ModelForm):
    class Meta:
        model=Aliment
        field = ('name','type_aliment_id','mesurande_id','calories','proteines')

views.py:

def add_aliment(request):
  add_aliment = AlimentForm()
  return render_to_response("add_aliment.html",
                          {'form_aliment':add_aliment,},RequestContext(request))

And I Would like to show all columns of "Aliment" but for "type_aliment_id" i would like to have a combobox with all names in "type_aliment" : And it doesn't work but i don't know why :

<form id="myForm" action="" method="post">{% csrf_token %}
  <select name="select_type" id="id_select_type">
    {% for type_aliment in form_aliment.type_aliment_id %}
    <option value="{{ type_aliment.id }}">{{ type_aliment.name}}</option>
    {% endfor %}
</select>

Upvotes: 1

Views: 67

Answers (1)

Selcuk
Selcuk

Reputation: 59228

You don't need to construct your combobox manually. It will automatically be created by Django. Just use

<form id="myForm" action="" method="post">
    {% csrf_token %}
    {{ form_aliment }}
    <button type="submit">Submit</button>
</select>

as the basis for your template.

You also have to implement the __unicode__ method in your class to see their names in the combo box:

class type_aliment(models.Model):
    ...
    def __unicode__(self):
        return self.name

PS: Your naming convention is confusing. Try to stick with Python/Django standards. Use CamelCase for class names; for example, instead of

class type_aliment(...)

use 

class TypeAliment(...)

and don't add the _id suffix to your field names. Instead of

type_aliment_id = models.OneToOneField(type_aliment)

use

type_aliment = models.OneToOneField(TypeAliment)

it will help fellow coders (like here on Stack Overflow) read your code more easily.

Upvotes: 2

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