Reputation: 1402
I have multiple tables inside div with same columns and I want them to convert to one table with all records from that tables.
Can it be done with jQuery?
My HTML looks like this:
<div id="multiTabels">
<table id="table1">
<tr>
<th>Column 1</th>
<th>Column 2</th>
</tr>
<tr>
<td>Record 1</td>
<td>Record 2</td>
</tr>
</table>
<table id="table1">
<tr>
<th>Column 1</th>
<th>Column 2</th>
</tr>
<tr>
<td>Record 3</td>
<td>Record 4</td>
</tr>
</table>
</div>
Upvotes: 1
Views: 1691
Reputation: 3830
Try this:
$(document).ready(function (){
$("#multiTabels table tr").each(function(){
$("#newTable").append($(this)); //append to any new table
});
});
Upvotes: 1
Reputation: 3288
Anything can be done with jQuery.
There's a really big thing to point out with my jsFiddle: I am using the thead
and tbody
tags. This is really important for segregating rows and is a semantic step forward in HTML. If you inspect tables in your dev console, you'll notice most browsers automatically add a tbody
around all tr
elements in a table now, so it's good to start doing this.
https://jsfiddle.net/wumztk45/
// This binds a hook to the document.
// If any 'click' events happen to an element with the id "cruch" this event fires.
// This event will persist even when crunch is deleted, and is good
// for when binding to elements that may not exist at the time.
$(document).on('click', "#crunch", function(event) {
// Find our container.
var $multiTables = $("#multiTables"),
// Find all tables in our container.
$tables = $multiTables.children("table"),
// From all tables after the first, find all <tr> elements within <tbody> elements.
$rows = $tables.not(":first").children("tbody").children("tr");
// Append these rows to the first table's tbody.
$tables.first().children("tbody").append( $rows );
// Remove the other tables.
$tables.not(":first").remove();
// Disable this button.
$(this).prop( 'disabled', true );
} );
Upvotes: 1
Reputation: 28513
Try this :
$(function(){
var $firstTable = $('#multiTabels table:first');
$('#multiTabels table:not(:first)').each(function(){
$firstTable.append($(this).find('tr').has('td'));
$(this).remove();
});
});
Upvotes: 1