Reputation: 1383
Is there a good way to convert a Vec<T>
with size S
to an array of type [T; S]
? Specifically, I'm using a function that returns a 128-bit hash as a Vec<u8>
, which will always have length 16, and I would like to deal with the hash as a [u8, 16]
.
Is there something built-in akin to the as_slice
method which gives me what I want, or should I write my own function which allocates a fixed-size array, iterates through the vector copying each element, and returns the array?
Upvotes: 137
Views: 135775
Reputation: 430368
Arrays must be completely initialized, so you quickly run into concerns about what to do when you convert a vector with too many or too few elements into an array. These examples simply panic.
As of Rust 1.51 you can parameterize over an array's length.
use std::convert::TryInto;
fn demo<T, const N: usize>(v: Vec<T>) -> [T; N] {
v.try_into()
.unwrap_or_else(|v: Vec<T>| panic!("Expected a Vec of length {} but it was {}", N, v.len()))
}
As of Rust 1.48, each size needs to be a specialized implementation:
use std::convert::TryInto;
fn demo<T>(v: Vec<T>) -> [T; 4] {
v.try_into()
.unwrap_or_else(|v: Vec<T>| panic!("Expected a Vec of length {} but it was {}", 4, v.len()))
}
As of Rust 1.43:
use std::convert::TryInto;
fn demo<T>(v: Vec<T>) -> [T; 4] {
let boxed_slice = v.into_boxed_slice();
let boxed_array: Box<[T; 4]> = match boxed_slice.try_into() {
Ok(ba) => ba,
Err(o) => panic!("Expected a Vec of length {} but it was {}", 4, o.len()),
};
*boxed_array
}
See also:
Upvotes: 134