CODEWITHSUNDEEP
c++c++11stlsetw
Raid Force
Raid Force

Reputation: 5

C++ manipulation using iomanip library

I am new to C++ STL libraries and need help.
I want to add two numbers suppose A = 4555 and B = 50, and output them as:

4555
  +50
4605

Another Examples:

500000 + 12

500000
      +12
500012

If i am storing both A and B in integer data type while the sign '+' in character data type. How can i manipulate them to get the preferred output. I just cant figure out how to manipulate two variables together.

Upvotes: 0

Views: 644

Answers (3)

randag
randag

Reputation: 422

In your example the fields can fit a maximum number of 7 characters. Perhaps you want to resize the strings to 7 before writing. e.g. fname.resize(7).

To format it as you want you need to #include <iomanip> and use std::left and std::setw(7).

file1 << left << setw(7) << fname
      << tab << setw(7) << lname
      << tab << setw(7) << street
      << tab << setw(7) << city
      << tab << setw(7) << state
      << tab << setw(7) << zip << endl;

Upvotes: 0

user2249683
user2249683

Reputation:

You might utilize the manipulators std::showpos, std::noshowpos and std::setw:

#include <iostream>
#include <iomanip>

int main() {
    int a = 4555;
    int b = 50;
    std::cout
        << std::noshowpos << std::setw(10) << a << '\n'
        << std::showpos   << std::setw(10) << b << '\n'
        << std::noshowpos << std::setw(10) << (a+b) << '\n';
}

If you want a width depending on the values you may use three std::ostringstream(s) and create intermediate strings (without setw). After that you print the strings using the maximal length of each for setw:

#include <algorithm>
#include <iostream>
#include <iomanip>
#include <sstream>

int main() {
    int a = 4555;
    int b = 50;

    std::ostringstream as;
    std::ostringstream bs;
    std::ostringstream rs;
    as << std::noshowpos << a;
    bs << std::showpos   << b;
    rs << std::noshowpos << (a+b);
    unsigned width = std::max({ as.str().size(), bs.str().size(), rs.str().size() });
    std::cout
        << std::setw(width) << as.str() << '\n'
        << std::setw(width) << bs.str() << '\n'
        << std::setw(width) << rs.str() << '\n';
}

See also:

Note: You may have a look at the manipulator std::internal.

Upvotes: 2

Sarfaraz Nawaz
Sarfaraz Nawaz

Reputation: 361362

If you could use constant width (or variable width equal to the maximum width of the numbers involved) with std::setw from <iomanip> as:

#include <iostream>
#include <iomanip>
#include <string>

void display_sum(int a, int b)
{
    std::cout << std::setw(10) << a  << "\n"
              << std::setw(10) << ("+" + std::to_string(b)) << "\n"
              << std::setw(10) << (a+b) <<"\n" << std::endl;
}

int main()
{
    display_sum(4555, 50);
    display_sum(500000, 12);
    display_sum(503930, 3922);
}

Output:

  4555
   +50
  4605

500000
   +12
500012

503930
 +3922
507852

Online demo

Upvotes: 0

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