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arraysjsonswiftswifty-json
μολὼν.λαβέ
μολὼν.λαβέ

Reputation: 668

Another:: How do I loop through json data with swiftyjson?

I'm evaluating swiftyJSON by trying something simple first and wondering what is the issue with this loop.

Here's sample data.

{
    "dataplot2d": [
        [0.25,2.3 ],
        [-2.5,8.09 ],
        [5.3145,20.205]
    ]
}

and here is code to read it into two separate arrays

var x:[Float] = []
var y:[Float] = []
var i:Int = 0
var t:Int = 0

var jsonArr = json["dataplot2d"].arrayValue

for ( i=0; i<jsonArr.count; i++ )//number of data points
{
    println("i \(i) t \(t) \(jsonArr[i][t])")
    x.append(jsonArr[i][0].array)
    y.append(jsonArr[i][1].array)
}

The error is Could not find member 'array' ??

array is defined https://github.com/SwiftyJSON/SwiftyJSON for arrayValue

//Non-optional [JSON]
public var arrayValue: [JSON] {
    get {
        return self.array ?? []
    }
}

What am I missing?

Maybe this would be cleaner without swiftyJSON??

Upvotes: 0

Views: 384

Answers (2)

Eric Aya
Eric Aya

Reputation: 70098

Note: I'm transforming my comment into an answer so I can post code.

In your code, jsonArr is your first-level array of arrays, so jsonArr[i] is an array of floats, and jsonArr[i][0] is a float, not an array. That was the source of the confusion. :)

As for the simplicity of the code, here's the same loop as yours but with a slightly "Swifter" syntax (I had to adapt the code a bit to make it work in a Playground, but it doesn't change anything to our matter):

var x:[Float] = []
var y:[Float] = []

let jsonArr: [[Float]] = [[0.25,2.3 ],[-2.5,8.09 ],[5.3145,20.205]]

for floatArray in jsonArr {
  x.append(floatArray[0])  // In your case, floatArray[0].float
  y.append(floatArray[1])
}

Upvotes: 1

μολὼν.λαβέ
μολὼν.λαβέ

Reputation: 668

Simply needed to unwrap to float, too bad this isn't really documented anywhere.

x.append(jsonArr[i][0].array)
y.append(jsonArr[i][1].array)

is

  x.append(jsonChart[i][0].float! )
  y.append(jsonChart[i][1].float! )

Upvotes: 0

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