CODEWITHSUNDEEP
javahashmapjava-8collectors
Deepak Shajan
Deepak Shajan

Reputation: 921

Hashmap with Streams in Java 8 Streams to collect value of Map

Let consider a hashmap

Map<Integer, List> id1 = new HashMap<Integer,List>();

I inserted some values into both hashmap.

For Example,

List<String> list1 = new ArrayList<String>();

list1.add("r1");
list1.add("r4");

List<String> list2 = new ArrayList<String>();
list2.add("r2");
list2.add("r5");

List<String> list3 = new ArrayList<String>();
list3.add("r3");
list3.add("r6");

id1.put(1,list1);
id1.put(2,list2);
id1.put(3,list3);
id1.put(10,list2);
id1.put(15,list3);

Q1) Now I want to apply a filter condition on the key in hashmap and retrieve the corresponding value(List).

Eg: Here My query is key=1, and output should be 'list1'

I wrote

id1.entrySet().stream().filter( e -> e.getKey() == 1);

But I don't know how to retrieve as a list as output of this stream operation.

Q2) Again I want to apply a filter condition on the key in hashmap and retrieve the corresponding list of lists.

Eg: Here My query is key=1%(i.e key can be 1,10,15), and output should be 'list1','list2','list3'(list of lists).

Upvotes: 78

Views: 284515

Answers (8)

Omkar
Omkar

Reputation: 21

    HashMap<Integer, String> hashmap = new HashMap<>();
    hashmap.put(1, "a");
    hashmap.put(2, "b");
    List<String> collect = hashmap.keySet().stream()
                            .map(k -> "key=" + k + " value=" + hashmap.get(k))
                            .collect(Collectors.toList());
    System.out.println(collect);

Upvotes: 0

YoHaRo
YoHaRo

Reputation: 142

why all that !!!

List list1 = id1.get(1);

Upvotes: 0

vbg
vbg

Reputation: 768

Maybe the sample is oversimplified, but you don't need the Java stream API here. Just use the Map directly.

 List<String> list1 = id1.get(1); // this will return the list from your map

Upvotes: -1

Shreya Mour
Shreya Mour

Reputation: 21

Using keySet-

id1.keySet().stream()
        .filter(x -> x == 1)
        .map(x -> id1.get(x))
        .collect(Collectors.toList())

Upvotes: 2

Basit
Basit

Reputation: 8606

You can also do it like this

public Map<Boolean, List<Student>> getpartitionMap(List<Student> studentsList) {

    List<Predicate<Student>> allPredicates = getAllPredicates();
    Predicate<Student> compositePredicate =  allPredicates.stream()
                             .reduce(w -> true, Predicate::and)
     Map<Boolean, List<Student>> studentsMap= studentsList
                .stream()
                .collect(Collectors.partitioningBy(compositePredicate));
    return studentsMap;
}

public List<Student> getValidStudentsList(Map<Boolean, List<Student>> studentsMap) throws Exception {

    List<Student> validStudentsList =  studentsMap.entrySet()
             .stream()
             .filter(p -> p.getKey() == Boolean.TRUE)
             .flatMap(p -> p.getValue().stream())
             .collect(Collectors.toList());

    return validStudentsList;
}

public List<Student> getInValidStudentsList(Map<Boolean, List<Student>> studentsMap) throws Exception {

    List<Student> invalidStudentsList = 
             partionedByPredicate.entrySet()
             .stream()
             .filter(p -> p.getKey() == Boolean.FALSE)
             .flatMap(p -> p.getValue().stream())
             .collect(Collectors.toList());

    return invalidStudentsList;

}

With flatMap you will get just List<Student> instead of List<List<Student>>.

Thanks

Upvotes: 3

user2336315
user2336315

Reputation: 16067

For your Q2, there are already answers to your question. For your Q1, and more generally when you know that the key's filtering should give a unique value, there's no need to use Streams at all.

Just use get or getOrDefault, i.e:

List<String> list1 = id1.getOrDefault(1, Collections.emptyList());

Upvotes: 5

fge
fge

Reputation: 121720

What you need to do is create a Stream out of the Map's .entrySet():

// Map<K, V> --> Set<Map.Entry<K, V>> --> Stream<Map.Entry<K, V>>
map.entrySet().stream()

From the on, you can .filter() over these entries. For instance:

// Stream<Map.Entry<K, V>> --> Stream<Map.Entry<K, V>>
.filter(entry -> entry.getKey() == 1)

And to obtain the values from it you .map():

// Stream<Map.Entry<K, V>> --> Stream<V>
.map(Map.Entry::getValue)

Finally, you need to collect into a List:

// Stream<V> --> List<V>
.collect(Collectors.toList())

If you have only one entry, use this instead (NOTE: this code assumes that there is a value; otherwise, use .orElse(); see the javadoc of Optional for more details):

// Stream<V> --> Optional<V> --> V
.findFirst().get()

Upvotes: 48

Eran
Eran

Reputation: 393841

If you are sure you are going to get at most a single element that passed the filter (which is guaranteed by your filter), you can use findFirst :

Optional<List> o = id1.entrySet()
                      .stream()
                      .filter( e -> e.getKey() == 1)
                      .map(Map.Entry::getValue)
                      .findFirst();

In the general case, if the filter may match multiple Lists, you can collect them to a List of Lists :

List<List> list = id1.entrySet()
                     .stream()
                     .filter(.. some predicate...)
                     .map(Map.Entry::getValue)
                     .collect(Collectors.toList());

Upvotes: 106

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