Reputation: 13824
I have the code here (basically modified from Jquery Checkbox Button by changed $widget.find('input:radio')
in JS and type = "radio"
in html.
(What it basically does is that, it makes the radio look better and more user friendly than a plain radio box, I want a big button so maybe touchscreen users can have better experience)
HTML
<span class="button-checkbox">
<button type="button" class="btn btn-lg" data-color="primary">Option 1</button>
<input type="radio" class="hidden" name="group1" id="op1" checked />
</span>
<span class="button-checkbox">
<button type="button" class="btn btn-lg" data-color="primary">Option 2</button>
<input type="radio" class="hidden" name="group1" id="op2" />
</span>
JS
$(function () {
$('.button-checkbox').each(function () {
// Settings
var $widget = $(this),
$button = $widget.find('button'),
$checkbox = $widget.find('input:radio'),
color = $button.data('color'),
settings = {
on: {
icon: 'glyphicon glyphicon-check'
},
off: {
icon: 'glyphicon glyphicon-unchecked'
}
};
// Event Handlers
$button.on('click', function () {
$checkbox.prop('checked', !$checkbox.is(':checked'));
$checkbox.triggerHandler('change');
updateDisplay();
});
$checkbox.on('change', function () {
updateDisplay();
});
// Actions
function updateDisplay() {
var isChecked = $checkbox.is(':checked');
// Set the button's state
$button.data('state', (isChecked) ? "on" : "off");
// Set the button's icon
$button.find('.state-icon')
.removeClass()
.addClass('state-icon ' + settings[$button.data('state')].icon);
// Update the button's color
if (isChecked) {
$button
.removeClass('btn-default')
.addClass('btn-' + color + ' active');
}
else {
$button
.removeClass('btn-' + color + ' active')
.addClass('btn-default');
}
}
// Initialization
function init() {
updateDisplay();
// Inject the icon if applicable
if ($button.find('.state-icon').length == 0) {
$button.prepend('<i class="state-icon ' + settings[$button.data('state')].icon + '"></i> ');
}
}
init();
});
});
Here is demo: http://jsfiddle.net/9o41oykp/2/
Problem: The checked/unchecked style seems to be working but because this is radio so I need it to be mutual exclusive meaning that only 1 box can be checked (when you check a radio box, the rest (in same group) should become unchecked automatically), but right now as you see you can check more than one box (the style showing it), I need help with jQuery function to make it work.
Upvotes: 1
Views: 1608
Reputation: 207861
I updated the code to work with radio buttons. The problem was, when using this with checkboxes it will work because you can modify a single checkbox without having to worry about the siblings, but with radio buttons you have to run through all the siblings, checking/unchecking each one, which requires looping over the set every time you make a change.
(note that in the fiddle I exposed the radio buttons so you could see whether each was checked or not.)
$(function () {
$('.button-checkbox').each(function () {
// Settings
var $widget = $(this),
$button = $widget.find('button'),
$checkbox = $widget.find('input:radio'),
color = $button.data('color'),
settings = {
on: {
icon: 'glyphicon glyphicon-check'
},
off: {
icon: 'glyphicon glyphicon-unchecked'
}
};
// Event Handlers
$button.on('click', function () {
$checkbox.triggerHandler('change');
if ($(this).hasClass('btn-default')) {
$checkbox.prop('checked', !$checkbox.is(':checked'));
updateDisplay();
}
});
// Actions
function updateDisplay() {
$('.button-checkbox').each(function () {
var isChecked = $(this).find('input:radio').is(':checked');
// Set the button's state
$(this).find('button').data('state', (isChecked) ? "on" : "off");
// Set the button's icon
$(this).find('button').find('.state-icon')
.removeClass()
.addClass('state-icon ' + settings[$(this).find('button').data('state')].icon);
// Update the button's color
if (isChecked) {
$(this).find('button')
.removeClass('btn-default')
.addClass('btn-' + color + ' active');
} else {
$(this).find('button')
.removeClass('btn-' + color + ' active')
.addClass('btn-default');
}
})
}
// Initialization
function init() {
updateDisplay();
// Inject the icon if applicable
if ($button.find('.state-icon').length == 0) {
$button.prepend('<i class="state-icon ' + settings[$button.data('state')].icon + '"></i> ');
}
}
init();
});
});
Upvotes: 1