CODEWITHSUNDEEP
c++constructorcompilation
user3608663
user3608663

Reputation: 125

C++ does not name a type in Constructor definition

I try to compile my code, I pretty sure I made a mistake in my headers or in the compilation but I don't understand where. I know that this is a basic problem, and I read some other topic, but I really don't understand. And I watch some other code I wrote and I don't see any difference...

g++ -c main.cpp -o out

I don't understand the error, so I also try : 

g++ -c readFastqFile.cpp

The error 

readFastqFile.cpp:8:1: error: ‘readFastq’ does not name a type
 readFastq::readFastq(){ //Constructor

And my files are :

main.cpp

    #include <iostream>
    #include <string>

    #include "readFastqFile.hpp"

using namespace std;

int main(int argc, char *argv[]){
    cout << "hello" <<endl;
    //readFastq allReads;
    return 0;
}

readFastqFile.hpp

#ifdef READFASTQFILE_HPP
#define READFASTQFILE_HPP

#include <iostream>
#include <string>

using namespace std;

class readFastq{
    public:
        readFastq(); //constructor

    private:
        string readName;
        string sequence;
        string score;
};
#endif // READFASTQFILE_HPP

readFastqFile.cpp

 #include <string>
    #include <iostream>
#include "readFastqFile.hpp"

using namespace std;

readFastq::readFastq(){ //Constructor
    readName = "bla";
    cout << readName <<endl;
}

Thanks

Upvotes: 3

Views: 6419

Answers (1)

interjay
interjay

Reputation: 110146

#ifdef READFASTQFILE_HPP should be #ifndef READFASTQFILE_HPP. The #ifdef is causing the contents of readFastqFile.hpp to be ignored, so the class definition isn't being compiled.

See also Include guards

Upvotes: 5

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