CODEWITHSUNDEEP
c#winformslistbox
NFI78
NFI78

Reputation: 63

Open file from List Box C#

When I try to run this I get the same error every time telling me that the file has not been found, even though it clearly is in that folder. Any ideas on how I can fix this?

Thank You.

public TaskViewer()
    {
        InitializeComponent();

        DirectoryInfo dInfo = new DirectoryInfo(@"C:\\To-Do-List");

        FileInfo[] Files = dInfo.GetFiles("*.txt");

        foreach (FileInfo file in Files)
        {
            listBox1.Items.Add(file.Name);
            Path.GetDirectoryName(file.Name);
        }

    }

    private void listBox1_SelectedIndexChanged(object sender, EventArgs e)
    {
        string file = listBox1.SelectedItem.ToString();
        Process.Start(file);
    }

Upvotes: 0

Views: 1326

Answers (2)

DLeh
DLeh

Reputation: 24385

private void listBox1_SelectedIndexChanged(object sender, EventArgs e)
{
    string file = listBox1.SelectedItem.ToString();
    string fullFileName = Path.Combine(@"C:\To-Do-List", file);
    Process.Start(fullFileName);
}

Upvotes: 3

Blorgbeard
Blorgbeard

Reputation: 103437

You are putting file.Name in the list-box, but that doesn't include the full path.

It looks like you're trying to do something about that with your Path.GetDirectoryName(file.Name);, however, that function returns a string and you are just throwing it away.

Process.Start needs the full path, or it will look in the current directory (probably your bin folder).

So, the easy fix would be to use file.FullPath instead of file.Path.

That will cause the full path to appear in the list box, however. If you don't want that, the answer by DLeh works if all the files are in the same folder.

Upvotes: 2

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