CODEWITHSUNDEEP
pythonpandasiteratordataframegrouping
Bunny
Bunny

Reputation: 85

Iterating over groups (Python pandas dataframe)

I want to iterate over groups that are grouped by strings or dates.

df = pd.DataFrame({'A': ['foo', 'bar'] * 3,
                   'B': ['me', 'you', 'me'] * 2,
                   'C': [5, 2, 3, 4, 6, 9]}) 
groups = df.groupby('A')

For eg in this code, I have groups by their names 'foo' and 'bar', and I can loop over them using;

for name, group in groups:
   print name

My problem is I need to run another loop inside this loop and everytime I need to call different set of groups. like (assume groups has size n)

for name,group in groups:
   for name1 in range(name, name + 9):  # + 9 to get first 9 groups for every iteration`

Since, name is a string I am unable to do that. In short I just want a method by which I can access groups by numbers so that I can easily call required groups for computation. Something like

groups = df.group('A')
for i in range(0,n):
    print group(i)[] + group(i+1)[]

so if I have following groups [g1,g2,g3,g4,g5], i want to iteratively call them in pairs like [g1,g2], [g2,g3], [g3,g4] .... and take the intersection of the 2 groups of series everytime. I am looking for way to call groups [g1,g2,..g5] by index or some no. so that I can use them for loop operations. Currently only way I know to call groups is through the names of the group, as mentioned above in example 'foo' and 'bar'. I want power to do operations such as:

for name,group in groups-1:
   print gb.get_group(name)
   print gb.get_group(name+1)

I know this might be a simple problem, but I have been struggling for this part since a while. I would appreciate any kind of help.

Upvotes: 8

Views: 28698

Answers (2)

Hillary Murefu
Hillary Murefu

Reputation: 96

Since dict_keys in Python 3 are not subscriptable, change:

df.ix[groups.groups[keys[index]]]

to

df.ix[groups.groups[list(keys)[index]]]

Upvotes: 0

S Anand
S Anand

Reputation: 11938

The .groupby() object has a .groups attribute that returns a Python dict of indices. In this case:

In [26]: df = pd.DataFrame({'A': ['foo', 'bar'] * 3,
   ....:                    'B': ['me', 'you', 'me'] * 2,
   ....:                    'C': [5, 2, 3, 4, 6, 9]})

In [27]: groups = df.groupby('A')

In [28]: groups.groups
Out[28]: {'bar': [1L, 3L, 5L], 'foo': [0L, 2L, 4L]}

You can iterate over this as follows:

keys = groups.groups.keys()
for index in range(0, len(keys) - 1):
    g1 = df.ix[groups.groups[keys[index]]]
    g2 = df.ix[groups.groups[keys[index + 1]]]
    # Do something with g1, g2

However, please remember that using for loops to iterate over Pandas objects is generally slower than vector operations. Depending on what you need done, and if it needs to be fast, you may want to try other approaches.

Upvotes: 13

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