CODEWITHSUNDEEP
macosgcc
Merkurial
Merkurial

Reputation: 252

gcc "can't be more simple" program got Undefined symbols for architecture x86_64 compile error

Before posting this question I've read hundreds of Google search result pages, searching solution of this problem in vain. My program can't be more simple — these are the only 3 files:

test.h

#ifndef SYMBOL
#define SYMBOL 

#include <stdio.h>

void output(void);

#endif

test.c

#include "test.h"

void output(void)
{
  printf("%s\n", "Hello world");
}

untitled.c

#include <stdio.h>
#include "test.h"

void main()
{
  output();
  return;
}

I use terminal and enter the following command to compile:

gcc -o aaa untitled.c

Output should print the "Hello world", but instead it keeps throwing this error:

Undefined symbols for architecture x86_64:
  "_output", referenced from:
      _main in untitled-00f904.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)

I spent the whole day searching for solution, tried all the suggestions as possible but none helped.

Something notable: If I change the file included in untitled.c (#include "test.h" to #include "test.c"), compiler goes without problem.

Can someone please explain to me why, and how to resolve it?

Upvotes: 3

Views: 4605

Answers (1)

trojanfoe
trojanfoe

Reputation: 122391

You have to compile and link both source files into the executable; the linker is telling you it cannot find the output() function defined in test.c:

$ gcc -o aaa untitled.c test.c

Upvotes: 4

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