Reputation: 902
I wrote a program for this problem:
“Write a program that, given an array array[] of n numbers and another number x, determines whether or not there exist two elements in array whose sum is exactly x.”
Which is this:
boolean hasArrayTwoCandidates (int array[], int sum) {
int length = array.length;
quickSort(array, 0, length-1);
int first, last;
first = 0;
last = length-1;
while(first < last){
if( array[first] + array[last] == sum )
return true;
else if( array[first] + array[last] < sum )
first++;
else // array[i] + array[j] > sum
last--;
}
return false;
}
At first place, I don't know where should I put or add "quick sort" codes. I have this problem with other programs, as well; when I want to add written methods to the present one.
At second place, I don't know what should I write in my "main method"?
this is my quicksort codes:
public void sort(int[] values) {
if (values == null || values.length == 0){
return;
}
this.array = values;
length = values.length;
quickSort(this.array, 0, length - 1);
}
private void quickSort(int[] array, int low, int high) {
int i = low, j = high;
int pivot = array[low + (high-low)/2];
while (i <= j) {
while (array[i] < pivot) {
i++;
}
while (array[j] > pivot) {
j--;
}
if (i <= j) {
exchange(i, j);
i++;
j--;
}
}
if (low < j)
quickSort(array, low, j);
if (i < high)
quickSort(array, i, high);
}
private void exchange(int i, int j) {
int temp = array[i];
array[i] = array[j];
array[j] = temp;
}
actually, I dont know what should I write in my "main method" to run this program?
Upvotes: 1
Views: 201
Reputation: 552
Answering your questions: you can write methods and call them within the same class, just write them with the static modifier:
private static <return_type> <methodName> (<type> param1, <type> param2) {
// Your code here
}
For a program like this, I don't get why you are thinking about sorting the array before checking the sum of 2 numbers within it, when you could do all at once. Check out this code, this may shine a light on you. It is straight-forward and only to see if it clarifies your logic.
import java.util.Random;
public class VerifySum {
public static void main(String[] args) {
Random rand = new Random();
int[] array = new int[10];
// Produce a random number from 10 to 20
int randomSum = rand.nextInt(11) + 10;
// Fill out the array with random integers from 0 to 10
for (int i = 0; i < array.length; i++) {
array[i] = rand.nextInt(11);
}
// Check all array indexes against each other
for (int i = 0; i < array.length - 1; i++) {
for (int j = i + 1; j < array.length; j++) {
if (array[i] + array[j] == randomSum) {
System.out.println(array[i] + " + " + array[j] + " = " + randomSum);
}
}
}
// Print "x"
System.out.println("randomSum = " + randomSum);
// Print array for verification of the functionality
for (int i = 0; i < array.length; i++) {
System.out.println("array [" + i + "] = " + array[i]);
}
}
}
Sometimes making it simpler is more efficient. ;-)
Upvotes: 1
Reputation: 3507
you can put all those method in same class, make hasArrayTwoCandidates()
static
(Note that main method is static and a static method can have access only to static methods)
public static boolean hasArrayTwoCandidates (int array[], int sum) {
....
}
and in your main method you can test it like this :
public static void main(String[] args){
int[] arr = {2,5,12,5,2,7,15};
System.out.print(hasArrayTwoCandidates(arr, 27));
}
Upvotes: 4
Reputation: 584
For you Question you can do simply this kind of coding in main method:
public static void main(String[]args) {
int x = 20;
int[] arr = {2,5,4,10,12,5};
System.out.println(hasArrayTwoCandidates(arr,x));
}
make the methods static
static boolean hasArrayTwoCandidates (int array[], int sum)
But there are porblems in your coding:
private void exchange(int i, int j) {
int temp = array[i];
array[i] = array[j];
array[j] = temp;
}
Here the array is not defined. you'll get an error. you have to pass the array too to the method make it as.
private void exchange(int i, int j,int[] array)
But since you are not necessary to do sorting. I recommend this.
static boolean hasArrayTwoCandidates (int array[], int sum) {
boolean flag = false;
for(int i=0;i<array.length-1;i++){
for(int j=i+1;j<array.length ;j++){
if(array[i]+array[j] == sum)
flag = true;
}
}
return flag;
}
this will get one element and check while adding other elements that it is true
Then the main method come same way.
Upvotes: 4