CODEWITHSUNDEEP
phpoffsetexplode
Mark
Mark

Reputation: 75

Getting 2 last elements of a url address

I'm trying to reach only the the site name and the domain, for example in case of images.google.com/thisIsJustAnExample it will return google.com. this is what I tried to do,

  $url = 'https://images.google.com/thisIsJustAnExample';
  $zobrazeni = array();
  $zobrazeni = parse_url($url);
  $zobrazeni["host"] = explode(".", $zobrazeni["host"]);
  $zobrazeni["host"] = $zobrazeni["host"][count($zobrazeni["host"])-2] .".". $zobrazeni["host"][count($zobrazni["host"])-1];

And this is the Error I get:

Notice: Undefined offset: -1 in C:\xampp\htdocs\retezce.php on line 25

Notice: Undefined variable: zobrazni in C:\xampp\htdocs\retezce.php on line 25

Notice: Undefined offset: -1 in C:\xampp\htdocs\retezce.php on line 25

Upvotes: 0

Views: 73

Answers (2)

Elin
Elin

Reputation: 6770

There are a few ways to do this but one would be:

  $url = 'https://images.google.com/thisIsJustAnExample';
  $zobrazeni = array();
  $zobrazeni = parse_url($url);
  $zobrazeni = explode(".", $zobrazeni["host"]);
  $zobrazeni =  array_reverse($zobrazeni);
  $zobrazeni = $zobrazeni[1] . ' .' . $zobrazeni[0];

Or you could get the length of the array and use that instead of trying to subtract 2.

Upvotes: 0

Danny
Danny

Reputation: 871

just play with this code, it should print "google"."com" if thats what you meant. just remember that count($verb) (in case $verb is array) will return the number of the objects in the array.

$url = "http://stackoverflow.com/questions/29731201/getting-2-last-elements-of-a-url-address/29731258#29731258";
$verbs = explode('.', $url);

$domainName = explode('/', $verbs[count($verbs)-2]);
$domainExt = explode('/', $verbs[count($verbs)-1]);

echo $domainName[2] . "." . $domainExt[0];

Upvotes: 1

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