Reputation: 3
I need to transform an XML file which has this doctype in the header:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE DOC SYSTEM "ts.dtd">
<?xml-stylesheet type="text/css" href="ts.css"?>
Transformation is going fine but the doctype is gone after the XSL transforming, I have tried all sorts of settings on the XmlReaderSettings
but can't get it to work.
This is my code:
XslCompiledTransform xctTransformer = new XslCompiledTransform();
xctTransformer.Load(fiXSL.FullName);
XmlReaderSettings xrsReaderSettings = new XmlReaderSettings();
xrsReaderSettings.ConformanceLevel = ConformanceLevel.Document;
xrsReaderSettings.DtdProcessing = DtdProcessing.Ignore;
xrsReaderSettings.XmlResolver = null;
xrsReaderSettings.CloseInput = true;
xrsReaderSettings.IgnoreWhitespace = false;
XmlWriterSettings xwsWriterSettings = new XmlWriterSettings();
xwsWriterSettings.Indent = true;
XmlReader xrReader = XmlReader.Create(fiXML.FullName, xrsReaderSettings);
XmlWriter xwWriter = XmlWriter.Create(fiXML.FullName.Substring(0, fiXML.FullName.Length - 4) + "_TRANS.xml", xwsWriterSettings);
// Transform the XML using the XSL
xctTransformer.Transform(xrReader, xwWriter);
xctTransformer = null;
// Close reader + writer
xrReader.Close();
xwWriter.Close();
Upvotes: 0
Views: 1080
Reputation: 3
Another answer I just found out is textually adding it via the XSL this way:
<xsl:template match="/">
<xsl:text disable-output-escaping='yes'><!DOCTYPE DOC SYSTEM "ts.dtd"></xsl:text>
<xsl:copy>
<xsl:apply-templates select = "*|@*|comment()|processing-instruction()|text()"/>
</xsl:copy>
</xsl:template>
Upvotes: 0
Reputation: 167571
A DOCTYPE node is not part of the XSLT/XPath data model so you can't process and copy it with XSLT. If you want your final result to have a certain DOCTYPE declaration then the only way with XSLT is to make sure you have an xsl:output
in your stylesheet with the doctype-system="ts.dtd"
.
Upvotes: 1