CODEWITHSUNDEEP
c#regex
Milos
Milos

Reputation: 1465

Regular expression capture decimal number ignore character

Input string:

----------------------
Test Id:         
Some Id: 718489  

        517.1[2] g  
----------------------

Expression (\d+\.\d) captures 517.1. What I need is to capture 517.12 (without []). Is this possible with Regular expression ?

Upvotes: 0

Views: 72

Answers (2)

A. Tapper
A. Tapper

Reputation: 1271

As @Vedran stated in the comment. You cannot remove the brackets in a regex, the best you can do is to end up with two captures.

But if your able to process the response this could solve your problem:

var number = float.Parse(Regex.Match(@"(\d+\.(\d|\[|\])+)").Value.Replace("[", "").Replace("]", ""), CultureInfo.InvariantCulture.NumberFormat);

Upvotes: 3

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626728

You can match the whole number with the bracket and then replace the [ with string.Empty:

var input = "----------------------\r\nTest Id:         \r\nSome Id: 718489  \r\n\r\n        517.1[2] g  \r\n----------------------";
var rx = new Regex(@"(?>\b\d+\.\d\[\d+\b)");
var res = rx.Match(input).Value.Replace("[", string.Empty);

Output:

enter image description here

Note that (?>...) atomic grouping removes the backtracking that we are not really interested in in this case.

Upvotes: 1

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