CODEWITHSUNDEEP
iosobjective-cjsonswiftnsdictionary
Kumar Nitin
Kumar Nitin

Reputation: 1863

How to read dictionary list from socket connection?

Whats the right way to read the dictionaries from socket data of the form:

{"data": {"abc": [], "pqr": []}, "error": ""}{"data": {"abc": [], "pqr": []}, "error": ""}{"data": {"abc": [], "pqr": []}, "error": ""}{"data": {"abc": [], "pqr": []}, "error": ""}{"data": {"abc": [], "pqr": []}, "error": ""}

Notice there are independent json dictionaries and we need to convert that into list of dictionaries. We can always do so using stringByReplacingOccurrencesOfString method by replacing "}{". But is there a better approach?

Upvotes: 2

Views: 158

Answers (2)

Luca Davanzo
Luca Davanzo

Reputation: 21528

Suppose that you already put string-dictionary in a dictionary:

NSDictionary* jsonSocketData;

for(NSDictionary* data in jsonSocketData[@"data"]) {
   /* whatever */
   NSLog(@"%@", data[@"abc"]); 
}

By the way I hope result of your request is more like this:

{
    "result": [
        {
            "data": {
                "abc": [],
                "pqr": []
            },
            "error": ""
        },
        {
            "data": {
                "abc": [],
                "pqr": []
            },
            "error": ""
        }
    ]
}

If you have to convert your NSString (json) to NSDictionary:

NSString* jsonString = @"..";

NSData* data = [jsonString dataUsingEncoding:NSUTF8StringEncoding];

NSDictionary* json = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];

Edit

If string you posted is the exact string that you receive I would this trick (in this way the json will be well-formed):

NSString* response = @"...";
/* only if you are sure about format */
response = [response stringByReplacingOccurrencesOfString: @"}{" withString:@"},{"];
/* otherwise you can apply regex, defintely more flexible, with pattern "}(.?){" */
response = [NSString stringWithFormat:@"{\"result\":[%@]}", response];

After this trick, you can apply code above. Btw, in my opinion, best way is to have a well-formed json rather than apply boring and custom parsing.

Upvotes: 3

SARATH SASI
SARATH SASI

Reputation: 1415

var dictionary = ["key" : "value", "key1" : "value1", "key2" : "value2", "Key3" : "Value3"]

for (key, value) in companies 
{
    println("\(value)")
}

Upvotes: -1

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