CODEWITHSUNDEEP
rubyarrays
sams
sams

Reputation: 188

Ruby - putting array elements into another array in order

array1 = [ [a], [b], [c], [d], [e] ]

array2 = [1, 2, 3, 4, 5, ...]

How can I put each of the elements of array2 into each the elements of array1 to get something like:

array3 = [ [a, 1], [b, 2], [c, 3], [d, 4], ... ]

I'm trying something like array1.map { |a| [a, array2.each { |b| b}] }, but not really sure how to get it yet.

Thanks!

Upvotes: 2

Views: 650

Answers (2)

Cary Swoveland
Cary Swoveland

Reputation: 110685

array1 = [ ['a'], ['b'], ['c'], ['d','e'] ]
array2 = [1, 2, 3, 4]

If you do not wish to alter array1 or array2: 

array1.zip(array2).map { |a1,e2| a1 + [e2] }
  #=> [["a", 1], ["b", 2], ["c", 3], ["d", "e", 4]]
array1
  #=> [ ['a'], ['b'], ['c'], ['d','e'] ]

If you do wish to alter array1 but not array2: 

array1.zip(array2).map { |a1,e2| a1 << e2 }
  #=> [["a", 1], ["b", 2], ["c", 3], ["d", "e", 4]]
array1
  #=> [["a", 1], ["b", 2], ["c", 3], ["d", "e", 4]]

If you do wish to alter array1 and can also alter array2: 

array1.map { |a| a << array2.shift }
  #=> [["a", 1], ["b", 2], ["c", 3], ["d", "e", 4]] 
array1
  #=> [["a", 1], ["b", 2], ["c", 3], ["d", "e", 4]] 
array2
  #=> []

In the first two cases you could use Array#transpose instead of Array#zip by replacing array1.zip(array2) with [array1, array2].transpose.

Upvotes: 2

Nafaa Boutefer
Nafaa Boutefer

Reputation: 2359

Just try this using Array#flatten and Array#zip

array1 = [ ['a'], ['b'], ['c'], ['d'], ['e'] ]
array2 = [1, 2, 3, 4, 5]
array1.flatten.zip(array2) 
# [["a", 1], ["b", 2], ["c", 3], ["d", 4], ["e", 5]]

More information about Array#zip can be found here.

Upvotes: 8

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