Reputation: 3923
I include myscript.js in the file http://site1.com/index.html
like this:
<script src=http://site2.com/myscript.js></script>
Inside "myscript.js", I want to get access to the URL "http://site2.com/myscript.js". I'd like to have something like this:
function getScriptURL() {
// something here
return s
}
alert(getScriptURL());
Which would alert "http://site2.com/myscript.js" if called from the index.html mentioned above.
Upvotes: 110
Views: 93177
Reputation: 15435
Everything except IE supports
document.currentScript
Eg
document.currentScript.src
Upvotes: 73
Reputation: 8343
Simple and straightforward solution that work very well :
If it not IE you can use document.currentScript
For IE you can do document.querySelector('script[src*="myscript.js"]')
so :
function getScriptURL(){
var script = document.currentScript || document.querySelector('script[src*="myscript.js"]')
return script.src
}
In a module script, you can use:
import.meta.url
as describe in mdn
Upvotes: 28
Reputation: 4938
Some necromancy, but here's a function that tries a few methods
function getScriptPath (hint) {
if ( typeof document === "object" &&
typeof document.currentScript === 'object' &&
document.currentScript && // null detect
typeof document.currentScript.src==='string' &&
document.currentScript.src.length > 0) {
return document.currentScript.src;
}
let here = new Error();
if (!here.stack) {
try { throw here;} catch (e) {here=e;}
}
if (here.stack) {
const stacklines = here.stack.split('\n');
console.log("parsing:",stacklines);
let result,ok=false;
stacklines.some(function(line){
if (ok) {
const httpSplit=line.split(':/');
const linetext = httpSplit.length===1?line.split(':')[0]:httpSplit[0]+':/'+( httpSplit.slice(1).join(':/').split(':')[0]);
const chop = linetext.split('at ');
if (chop.length>1) {
result = chop[1];
if ( result[0]!=='<') {
console.log("selected script from stack line:",line);
return true;
}
result=undefined;
}
return false;
}
ok = line.indexOf("getScriptPath")>0;
return false;
});
return result;
}
if ( hint && typeof document === "object") {
const script = document.querySelector('script[src="'+hint+'"]');
return script && script.src && script.src.length && script.src;
}
}
console.log("this script is at:",getScriptPath ())
Upvotes: 0
Reputation: 5971
document.currentScript.src
will return the URL of the current Script URL.
Note: If you have loaded the script with type Module
then use
import.meta.url
for more import.meta & currentScript.src
Upvotes: 2
Reputation: 9050
You can add id attribute to your script tag (even if it is inside a head tag):
<script id="myscripttag" src="http://site2.com/myscript.js"></script>
and then access to its src as follows:
document.getElementById("myscripttag").src
of course id value should be the same for every document that includes your script, but I don't think it is a big inconvenience for you.
Upvotes: 61
Reputation: 4396
Following code lets you find the script element with given name
var scripts = document.getElementsByTagName( 'script' );
var len = scripts.length
for(var i =0; i < len; i++) {
if(scripts[i].src.search("<your JS file name") > 0 && scripts[i].src.lastIndexOf("/") >= 0) {
absoluteAddr = scripts[i].src.substring(0, scripts[i].src.lastIndexOf("/") + 1);
break;
}
}
Upvotes: 2
Reputation: 10834
I wrote a class to find get the path of scripts that works with delayed loading and async script tags.
I had some template files that were relative to my scripts so instead of hard coding them I made created the class to do create the paths automatically. The full source is here on github.
A while ago I had use arguments.callee to try and do something similar but I recently read on the MDN that it is not allowed in strict mode.
function ScriptPath() {
var scriptPath = '';
try {
//Throw an error to generate a stack trace
throw new Error();
}
catch(e) {
//Split the stack trace into each line
var stackLines = e.stack.split('\n');
var callerIndex = 0;
//Now walk though each line until we find a path reference
for(var i in stackLines){
if(!stackLines[i].match(/http[s]?:\/\//)) continue;
//We skipped all the lines with out an http so we now have a script reference
//This one is the class constructor, the next is the getScriptPath() call
//The one after that is the user code requesting the path info (so offset by 2)
callerIndex = Number(i) + 2;
break;
}
//Now parse the string for each section we want to return
pathParts = stackLines[callerIndex].match(/((http[s]?:\/\/.+\/)([^\/]+\.js)):/);
}
this.fullPath = function() {
return pathParts[1];
};
this.path = function() {
return pathParts[2];
};
this.file = function() {
return pathParts[3];
};
this.fileNoExt = function() {
var parts = this.file().split('.');
parts.length = parts.length != 1 ? parts.length - 1 : 1;
return parts.join('.');
};
}
Upvotes: 20
Reputation: 6396
if you have a chance to use jQuery, the code would look like this:
$('script[src$="/myscript.js"]').attr('src');
Upvotes: 15
Reputation: 9926
From http://feather.elektrum.org/book/src.html:
var scripts = document.getElementsByTagName('script');
var index = scripts.length - 1;
var myScript = scripts[index];
The variable myScript
now has the script dom element. You can get the src url by using myScript.src
.
Note that this needs to execute as part of the initial evaluation of the script. If you want to not pollute the Javascript namespace you can do something like:
var getScriptURL = (function() {
var scripts = document.getElementsByTagName('script');
var index = scripts.length - 1;
var myScript = scripts[index];
return function() { return myScript.src; };
})();
Upvotes: 62
Reputation: 2769
Can't you use location.href or location.host and then append the script name?
Upvotes: -6