CODEWITHSUNDEEP
javascriptphpjqueryajax
yooouuri
yooouuri

Reputation: 2658

How can i tell PHP which form is submitted

Is there a way to tell PHP which form has been submitted?

Form 1

<form id="factory" action="bullets.php" method="post">
    <input type="submit" value="Kopen">
</form>

And form 2

<form id="localFactory" action="bullets.php" method="post">
    <input type="submit" value="Kopen">
</form>

These forms are on one page.

My javascript code:

    var url;

    $('form').submit(function (event) {
        event.preventDefault();

        url = $(this).attr('action');

        location.hash = url;

        $.ajax ({
            url: url,
            method: 'POST',
            data: $(this).serialize()
        }).done(function (html) {
            $('#content').html(html);
        });
    });

If i got an input i get a $_POST variable.

So i need to know which of the above forms has been submitted?

Thanks..

Upvotes: 0

Views: 85

Answers (4)

Outpox
Outpox

Reputation: 129

If you want an html only solution, you could add a hidden input with the form id: 

<form id="factory" action="bullets.php" method="post">
    <input type="hidden" value="factory" name="formId"/>
    <input type="submit" value="Kopen">
</form>

And then test it with: 

if (isset($_POST['formId']) && $_POST['formId'] == 'factory') { 
   //Do what you want here
}

Upvotes: 0

Flosculus
Flosculus

Reputation: 6946

By namespacing the input fields, you can easily identify which fields are from which form, and by extension which form was submitted.

<form id="factory" action="bullets.php" method="post">
    <input type="text" name="form_1[my_input]">
    <input type="submit" value="Kopen">
</form>

<form id="localFactory" action="bullets.php" method="post">
    <input type="text" name="form_2[my_input]">
    <input type="submit" value="Kopen">
</form>

Then it is as simple as:

if (isset($_POST['form_1'])) { 
    // This post variable is an array of each field.
}

Upvotes: 0

lshas
lshas

Reputation: 1731

This will work:

var url;

$('form').submit(function (event) {
    event.preventDefault();

    url = $(this).attr('action');

    location.hash = url;
    var data = $(this).serialize();
    data += "&formId=" + encodeURIComponent($(this).attr('id')); // if you have data in the form.
    // do this if you don`t have data in the form:
    // data = {formId: $(this).attr('id')};

    $.ajax ({
        url: url,
        method: 'POST',
        data: data
    }).done(function (html) {
        $('#content').html(html);
    });
});

You can then get the forms Id from $_POST['formId']

Upvotes: 3

sroes
sroes

Reputation: 15053

Create a submit button with a name:

<form id="factory" action="bullets.php" method="post">
    <button type="submit" value="factory" name="submit">Kopen</button>
</form>

This value is now posted:

if (!empty($_POST['submit']) && $_POST['submit'] == 'factory') { 

}

Upvotes: 1

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