Reputation: 1166
I have two activities "A" and "B".
In my "A" activity I use startActivityForResult:
Intent i = new Intent(A.this, B.class);
setResult(RESULT_OK, i);
startActivityForResult(i, 121245);
finish();
This is the code of my "B" activity:
@Override
public void onActivityResult(int requestCode, int resultCode, Intent intent) {
Toast.makeText(B.this, "onActivityResult", Toast.LENGTH_SHORT).show();
if(requestCode == 121245) {
if (resultCode == RESULT_OK)
//make something
}
}
Why my Toast doesn't show?
Upvotes: 0
Views: 1121
Reputation: 1853
onActivityResult
will be called on the activity which is starting the activity for result, meaning calls the startActivityForResult
method
What that means is if you want to be notified when the B activity finishes in A activity, you would first in A activity start the B activity like you did in your example code
Intent i = new Intent(A.this, B.class);
setResult(RESULT_OK, i);
startActivityForResult(i, 121245);
then when B activity finishes A activity's onActivityResult
is called and there you can do whatever you want.
Here's a diagram if it helps you understand the flow of the application
Upvotes: 9
Reputation: 1000
You have a little mistake
at A class should be:
Intent i = new Intent(A.this, B.class);
startActivityForResult(i, 121245);
at B class to return:
Intent i = new Intent();
setResult(RESULT_OK, i);
finish();
and handle it at A
@Override
public void onActivityResult(int requestCode, int resultCode, Intent intent) {
Toast.makeText(B.this, "onActivityResult", Toast.LENGTH_SHORT).show();
if(requestCode == 121245) {
if (resultCode == RESULT_OK)
//make something
}
}
Upvotes: 5
Reputation: 1838
onActivityResult()
must be the part of your A activity, Your B activity will return some data back to A and then onActivityResult()
will be called.
Upvotes: 1