CODEWITHSUNDEEP
javascriptphpjquery
Marco Ripamonti
Marco Ripamonti

Reputation: 99

Pass php variable to jquery script is not working

I have the following jquery script:

<script>
        $(document).ready(function () {
            $(".clickable").click(function () {
                $(this).animate({left: '1030px'}, function () {
                    $(this).fadeOut("slow", function () {
                        document.location.href = $(this).get(0).id + ".php";
                    });
                });
            });

        });
        $(document).ready(function () {
            $("#Chi").animate({left: '0'}, {duration: 200, queue: false});
            $("#Dove").animate({left: '0'}, {duration: 400, queue: false});
            $("#Quando").animate({left: '0'}, {duration: 600, queue: false});
            $("#Cosa").animate({left: '0'}, {duration: 800, queue: false});
            var phpvariable=<? echo $row; ?>
            $('.dreams-photo-profile-mydream').css({"background": "url(\"/images/user.png\")"});
            $('.dreams-photo-profile-mydream').css({"background-repeat": "no-repeat"});
            $('.dreams-photo-profile-mydream').css({"background-position": "center"});
            $('.dreams-photo-profile-mydream').css({"background-size": "contain"});

        });

    </script>

And i'm trying to pass a php variable like so:

   <?php
    $gdb->connettiDB();
    $row = $gdb->getFotoProfilo(getId());
    ?>

 var phpvariable=<? echo $row; ?>

That 's not working. When i declare a var inside the script, everything seems blocked and my animations aren't working and I don't know why. Can anyone explain me how can I exactly do that?

Upvotes: 0

Views: 1182

Answers (3)

jeroen
jeroen

Reputation: 91734

The correct way to pass variables from php to javascript, is to use json_encode:

var phpvariable=<?php echo json_encode($row); ?>;

Now the php will not accidentally break your javascript regardless of the type of variable that is $row. And the name suggests something like an array...

If $row is an integer, the problem could also have been caused by a missing short-tag setting in php. That's why I have used <?php in my example.

Lastly, a missing ; after your variable declaration in javascript, could also cause problems but that would depend on what comes after it.

Upvotes: 1

enigma
enigma

Reputation: 3491

You need to make sure the html containing the <script> you've posted above is in the same file. The $row variable needs to be defined before the <script>.

You are also missing a ; at the end of the javascript line

var phpvariable=<? echo $row; ?>;

If $row is a string, you also need to use ":

var phpvariable="<? echo $row; ?>";

Upvotes: 0

Saty
Saty

Reputation: 22532

Wrong use of php:-

var phpvariable=<? echo $row; ?>

It should be

 var your_variable='<?php echo $row; ?>';

Upvotes: 1

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