CODEWITHSUNDEEP
javastringloopscompareto
Stewart
Stewart

Reputation: 25

I'm trying to check if a word is abecedarian using compareTo

I would like to keep my program pretty much the same. I've used a lot of String methods like charAt, substring and indexOf. A word is said to be “abecedarian” if the letters in the word appear in alphabetical order.

import java.util.*;

public class Abecedarian{
    public static void main( String[] args ){
        String word=getWord();

    }

    public static String getWord(){
        Scanner keyboard = new Scanner(System.in);
        String word;
        System.out.print("Enter a word: ");
        word=keyboard.nextLine();
        return word;
    }

    public static boolean isAbecedarian(String word){

Upvotes: 1

Views: 3341

Answers (2)

Mureinik
Mureinik

Reputation: 311796

You could iterate over the characters in the word and make sure they are in ascending alphabetical order:

public static boolean isAbecedarian (String word) {
    int length = word.size();
    if (length <= 1) {
        return true;
    }

    word = word.toLowerCase(); // just in case

    char prev; 
    char curr;

    for (int i = 1; i < length; ++i) {
        prev = word.charAt(i - 1);
        curr = word.charAt(0);
        if (prev > curr) {
            return false;
        }
    }

    return true;
}

Upvotes: 2

SMA
SMA

Reputation: 37053

Try using:

if (word.compareTo("abecedarian") == 0) {
   //yes it is equal
}

There's better way of checking for equality using equals method of String like:

if ("abecedarian".equals(word)) {
    ...
}

Upvotes: 0

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