CODEWITHSUNDEEP
javapriority-queue
user3072188
user3072188

Reputation: 305

Add Key and Value into an Priority Queue and Sort by Key in Java

I am trying to take in a List of strings and add them into a Priority Queue with Key and Value. The Key being the word and the value being the string value of the word. Then I need to sort the queue with the highest string value first. The priority queue is not letting me add 2 values. 

public static List<String> pQSortStrings(List<String> strings) {
    PriorityQueue<String, Integer> q = new PriorityQueue<>();

    for (int x = 0; x < strings.size(); x++) {
        q.add(strings.get(x),calculateStringValue(strings.get(x)));
    }
    return strings;
}

Upvotes: 17

Views: 65968

Answers (6)

Rohan RM
Rohan RM

Reputation: 157

Define a class with a key field and a value field

Class MyClass{
    int key;
    String value
}

Queue<MyClass> queue = new PriorityQueue<>(Comparotor.comparingInt(a -> a.key));

Upvotes: 1

vishal patel
vishal patel

Reputation: 193

Many good answers are already present but I am posting this answer because no one has used hashmap in their answers.

You can also make the priority Queue from HashMaps bellow is the example for the same. I am creating a max priority queue. Mind well here I am considering that your hashmap contains only one Entry

PriorityQueue<HashMap<Character, Integer>> pq = new PriorityQueue<>((a, b) -> {
        char keyInA = a.keySet().iterator().next(); // key of a
        char keyInB = b.keySet().iterator().next(); // key of b
        return b.get(keyInB) - a.get(keyInA);
    });

For Insertion of the value in the priority queue.

pq.add(new HashMap<>() {
            {
                put('a', 0);
            }
        });

Upvotes: 0

mss
mss

Reputation: 1493

Adding to @Tanmay Patil Answer, If you are using Java 8, You can use lambda for more concise code as comparator interface is a functional interface.

public class CustomEntry {
    private String key;
    private int value;

    public CustomEntry(String key, int value) {
        this.key = key;
        this.value = value;
    }

    // getters etc.
}

Now below is the updated code

public static List<String> pQSortStrings(List<String> strings) {
    PriorityQueue<CustomEntry> q = new PriorityQueue<>((x, y) -> {
        // since you want to sort by highest value first
        return Integer.compare(y.getValue(), x.getValue()); 
    });

    for (int x = 0; x < strings.size(); x++) {
        q.add(new CustomEntry(strings.get(x),calculateStringValue(strings.get(x))));
    }
    return strings;
}

To use this priority queue

CustomEntry topEntry = q.peek();
System.out.println("key : " + topEntry.getKey());
System.out.println("value : " + topEntry.getValue());

Same logic can be also be applied by using Map.Entry<String, Integer> provided by java for storing key, pair value

Upvotes: 0

Ankit Sharma
Ankit Sharma

Reputation: 1654

Using Java-8

PriorityQueue<Map.Entry<String, Integer>> queue = new PriorityQueue<>(Map.Entry.comparingByValue(Comparator.reverseOrder()));

to add a new Entry

queue.offer(new AbstractMap.SimpleEntry<>("A", 10));

Upvotes: 21

Paul K.
Paul K.

Reputation: 21

Solution

public static List<String> pQSortStrings(List<String> strings) {    
    Queue<String> pq = new PriorityQueue<>((a, b) -> 
        calculateStringValue(b) - calculateStringValue(a));
    for (String str : strings) {
         pq.add(str);
    }
    return strings;
}

Explanation

I believe that the cleanest way to do this is to store Strings in your pq and use a small custom Comparator. In this case, we want to use calculateStringValue and the pq should return highest String values first. Therefore, make a pq of entries and use the following Comparator:

1   Queue<String> pq = new PriorityQueue<>(new Comparator<String>() {
2       @Override
3       public int compare(String a, String b) {
4           return calculateStringValue(b) - calculateStringValue(a);
5       }
6   });
7   for (String str : strings) {
8       pq.add(str);
9   }
10  return strings;

Simpler syntax for the Comparator, replacing lines 1 - 6, is:

Queue<String> pq = new PriorityQueue<>((a, b) -> 
    calculateStringValue(b) - calculateStringValue(a));

If you wanted to return smallest String values first, you could just switch the order around for a and b in the Comparator:

...new PriorityQueue<>((a, b) -> calculateStringValue(a) - calculateStringValue(b));

In general, the pattern a - b sorts by smallest first, and b - a sorts by largest values first.

Upvotes: 2

Tanmay Patil
Tanmay Patil

Reputation: 7057

Problem

PriorityQueue can store a single object in it's each node. So what you are trying to do can not be done as it is.

But you can compose both objects in a single class and then use the PriorityQueue.

You would either need to supply a Comparator or rely on natural ordering by implementing Comparable interface.

Solution

  • Create a class which has String and int as it's members.

    public class Entry {
    private String key;
    private int value;

    // Constructors, getters etc.
}

  • Implement Comparable interface and delegate comparison to String.

    public class Entry implements Comparable<Entry> {
    private String key;
    private int value;

    public Entry(String key, int value) {
        this.key = key;
        this.value = value;
    }

    // getters

    @Override
    public int compareTo(Entry other) {
        return this.getKey().compareTo(other.getKey());
    }
}

  • Build the PriorityQueue using this class.

    PriorityQueue<Entry> q = new PriorityQueue<>();

  • Add elements as following.

    q.add(new Entry(strings.get(x), calculateStringValue(strings.get(x))));

Hope this helps.

Upvotes: 27

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