Reputation: 73
I have an example table like this:
Month City Person
8 LHR ABC
10 BEIJING BCS
11 NY JJJ
11 VENICE hghg
11 VENICE KKK
12 NY aa
12 ORL abc
12 ORL bbc
So what I want to achieve is see the city in a specific month with the most number of people visiting
Like the output should be:
12 ORL
11 VENINCE
10 BEIJING
8 LHR
I have tried grouping it like
SELECT month, city , count(*) AS 'no of people visiting'
FROM table
GROUP BY month, city
This table does tell me which city and month location had how many people
visiting but I cannot extract the the top most month and city combination
with respect to a certain month.
Updated Query (with error)
SELECT *
FROM
( SELECT monthname(reservation.PickupDate), location.LocationName, COUNT(*) AS count
FROM reservation NATURAL JOIN location
WHERE reservation.pickupdate >= DATE_ADD(NOW(), INTERVAL - 3 MONTH)
GROUP BY month(reservation.PickupDate), location.LocationName) AS t1
WHERE NOT EXISTS (SELECT 1
FROM reservation R1 NATURAL JOIN location L1
WHERE monthname(R1.PickupDate) = monthname(t1.PickupDate)
GROUP BY month(R1.PickupDate), L1.LocationName)
Upvotes: 2
Views: 41
Reputation: 1590
Starting from your query, you just need to eliminate those rows having another city with more visitors on that month:
SELECT *
FROM
(SELECT `month`, city, count(*) AS cnt
FROM `table`
GROUP BY `month`, city) t1
WHERE NOT EXISTS(SELECT 1
FROM `table` t2
WHERE t2.`month` = t1.`month`
GROUP BY `month`, city
HAVING count(*) > t1.cnt)
Upvotes: 1