Reputation: 348
I want to extract matched parts of strings --digital part from an array
array("HK00003.Day","HK00005.Day")
.
<?php
$arr=array("HK00003.Day","HK00005.Day");
$result= array();
foreach ($arr as $item){
preg_match('/[0-9]+/',$item,$match);
array_push($result,$match[0]);
}
It can get the result :00003
00005
,it seems tedious,preg_grep seems simple but the result is not what i want .
preg_grep('/[0-9]+/',$arr);
The output is "HK00003.Day","HK00005.Day", not 00003
00005
,
is there more simple way to get the job done?
Upvotes: 1
Views: 51
Reputation: 59681
This should work for you:
(Here I just get rid off every character in your array which isn't a number with preg_replace()
)
<?php
$arr = ["HK00003.Day", "HK00005.Day"];
$result = preg_replace("/[^0-9]/", "", $arr);
print_r($result);
?>
output:
Array ( [0] => 00003 [1] => 00005 )
Upvotes: 1
Reputation: 436
preg_grep return array entries that match the pattern! Therefore, it returns an array of entry rather than the matching string
try below:
preg_match_all('/[0-9]+/',implode('-',$arr),$result);
Upvotes: 0
Reputation: 626748
You can use preg_filter
(which already uses preg_replace
and does not require additional callback functions) to replace the each entry in the array with the number inside:
<?php
$arr = array("HK00003.Day","HK00005.Day");
$matches = preg_filter('/^.*?([0-9]+).*/', '$1',$arr);
print_r($matches);
?>
Output of a sample program:
Array
(
[0] => 00003
[1] => 00005
)
Upvotes: 1
Reputation: 530
Your code is fine, not tedious at all. If you want a one-liner you can try something like this (remove everything that's not a digit):
array_push($result, preg_replace("~[^0-9]~", "", $item));
Upvotes: 0