CODEWITHSUNDEEP
c#wpfunit-testingxaml
Tomas Bruckner
Tomas Bruckner

Reputation: 728

C# Unit Test open Window.xaml

I need to open my Window.xaml in Unit Test. I tried a simple code as follows:

 [Test]
 public void Test_window()
 {
      var mw = new MainWindow();
      mw.Show();
 }

The above code ends with an error.

The calling thread must be STA, because many UI components require this.

Afterwards, I tried the below code :

     [Test]
     public void Test_window()
     {
        Thread th = new Thread(new ThreadStart(delegate
        {
            var mw = new MainWindow();
            mw.Show();
        }));

        th.ApartmentState = ApartmentState.STA;
        th.Start();

     }

In this case , the test passes successfully, but no window is shown. Since I am new to WPF, it would be appreciable if any suggestions or guidance are available here.

Thanks.

Upvotes: 3

Views: 4258

Answers (1)

Wojciech Kulik
Wojciech Kulik

Reputation: 8500

I think it is shown, but very fast, because you don't wait for the window. You could do something like this:

[Test]
public void Test_window()
{
    var showMonitor = new ManualResetEventSlim(false);
    var closeMonitor = new ManualResetEventSlim(false);

    Thread th = new Thread(new ThreadStart(delegate
    {
        var mw = new MainWindow();
        mw.Show();

        showMonitor.Set();
        closeMonitor.WaitOne();
    }));

    th.ApartmentState = ApartmentState.STA;
    th.Start();

    showMonitor.WaitOne();
    Task.Delay(1000).Wait();
    //anything you need to test
    closeMonitor.Set();
}

It is possible to achieve the same with only one monitor, but it's more readable in this way.

Upvotes: 3

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