CODEWITHSUNDEEP
pythonpython-zipfile
Julien
Julien

Reputation: 629

Create individual archives from individual folders with Zipfile

I have a directory composed of 3 folders :
----- 001
----- 002
----- 003

I'd like to create 3 archives named 001.zip, 002.zip and 003.zip. Each archive has to be composed of the content of the folder.

I use the zipfile library and I managed to make an archive of one folder :

import os, zipfile    
zf = zipfile.ZipFile('C:/zipfile4.zip', mode='w')
for dirpath,dirs,files in os.walk("C:/Test/002"):
    for f in files:
        fn = os.path.join(dirpath, f)
        zf.write(fn)

But I don't know how to make to create many archives in a row, using that zipfile library.

Upvotes: 0

Views: 80

Answers (1)

geckon
geckon

Reputation: 8774

Using your code sample as a basis, this should work:

import os
import zipfile

dir = "C:/Test/002"

# get list of all subdirectories in the directory
subdirs = [subdir for subdir in os.listdir(dir) if os.path.isdir(os.path.join(dir, subdir))]

# create a zip archive for each subdirectory
for subdir in subdirs:
    zf_name = "C:/" + subdir + ".zip"
    zf = zipfile.ZipFile(zf_name, mode='w')
    for dirpath,dirs,files in os.walk(os.path.join(dir, subdir)):
        for f in files:
            fn = os.path.join(dirpath, f)
            zf.write(fn)

Upvotes: 1

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