CODEWITHSUNDEEP
php
Nicholas
Nicholas

Reputation: 299

Random 4 digit number excluding numbers 8 and 9

I need to generate a random 4 digit number, but exclude 8 and 9 in the generation.

Here's the code I'm using now, but it obviously doesn't exclude 8 and 9,

rand(pow(10, 4 - 1), pow(10, 4) - 1);

Upvotes: 1

Views: 1023

Answers (3)

Jonathan Kuhn
Jonathan Kuhn

Reputation: 15301

This would work as well.

$allowedNumbers = range(0, 7);
$digits = array_rand($allowedNumbers, 4);
$number = '';
foreach($digits as $d){
    $number .= $allowedNumbers[$d];
}

echo $number;

Benefit here is you can specify the allowed characters by creating an array of allowed digits. It would also allow you to include really any character from an array including letters or words.

Upvotes: 3

cmorrissey
cmorrissey

Reputation: 8583

Something like?

$randomNumber = rand(0,7) . rand(0,7) . rand(0,7) . rand(0,7);

Upvotes: 2

Rizier123
Rizier123

Reputation: 59681

This should work for you:

Here I just get the random number with mt_rand() then I convert it to base 8 (0-7, means no 8 or 9) with base_convert(). And at the end I simply take the first 4 digits with substr().

echo $number = substr(base_convert(mt_rand(), 10, 8), 0, 4);

Upvotes: 2

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