CODEWITHSUNDEEP
angularjs
Samantha J T Star
Samantha J T Star

Reputation: 32808

How can I protect my .factory from minification?

I have this function in AngularJS. Can someone tell me how I can protect it so that it can be minified:

.factory('isEmailAvailable', function (appConstant, $q, $http) {
    return function (email) {
        var deferred = $q.defer();
        var url = appConstant.baseUrl + '/api/user/existsByEmail';
        $http({
            url: url,
            method: "PUT",
            data: {
                email: email
            }
        }).then(function () {
                // Found the user, therefore not unique.
                deferred.reject("User name is taken");
            }, function () {
                // User not found, therefore unique!
                deferred.resolve();
            });
        return deferred.promise;
    }
});

Upvotes: 1

Views: 47

Answers (1)

Michael Cole
Michael Cole

Reputation: 16217

I think what you mean is to protect dependency injection of this function: 

function (appConstant, $q, $http) {}

To do that, change it to an array, telling Angular what you are injecting:

['appConstant', '$q', '$http', function (appConstant, $q, $http) {}]

so it would look like this

.factory('isEmailAvailable', ['appConstant', '$q', '$http', function (appConstant, $q, $http) {
  // Your code here
}])

If you are using gulp to automate building your app (it's totally worth it), you can use the gulp-ng-annotate module to do this automatically without adding cruft to the original code.

Upvotes: 5

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