Reputation: 5122
I get:
(L1:268): JOIN (including semi-join) and UNION ALL (comma, date range) may not be combined in a single SELECT statement. Either move the UNION ALL to an inner query or the JOIN to an outer query.
query:
SELECT a AS a,
Count( DISTINCT b, 999999) AS b,
FROM [dataset.partition_20121216],
[dataset.partition_20130115],
[dataset.partition_20130214]
WHERE created BETWEEN Timestamp('2013-01-05 00:00:00') AND Timestamp ('2013-02-15 23:59:59.999999')
AND id IN (
SELECT id
FROM [dataset.partition_20121216],
[dataset.partition_20130115],
[dataset.partition_20130214]
WHERE created BETWEEN Timestamp('2013-01-05 00:00:00') AND Timestamp ('2013-02-15 23:59:59.999999')
AND name = 'G’
)
GROUP each a
ORDER BY a
What did I do wrong?
thanks.
Upvotes: 4
Views: 1946
Reputation: 521
The way I was able to go around this same issue was to use the subqueries in joins, rather than the where in syntax. Something along the lines of
SELECT
a,
COUNT(b)
FROM (
SELECT
id,
a,
b
FROM
[dataset.partition_20121216],
[dataset.partition_20130115],
[dataset.partition_20130214]
WHERE
created BETWEEN TIMESTAMP('2013-01-05 00:00:00')
AND Timestamp ('2013-02-15 23:59:59.999999') ) a
JOIN (
SELECT
DISTINCT id
FROM
[dataset.partition_20121216],
[dataset.partition_20130115],
[dataset.partition_20130214]
WHERE
created BETWEEN TIMESTAMP('2013-01-05 00:00:00')
AND Timestamp ('2013-02-15 23:59:59.999999')
AND name = 'G' ) b
ON
b.id = a.id
GROUP BY
a
ORDER BY
a
Upvotes: 0
Reputation: 13994
This is limitation of BigQuery SQL syntax, I would change it to
SELECT a AS a,
Count( DISTINCT b, 999999) AS b,
FROM
(SELECT * FROM
[dataset.partition_20121216],
[dataset.partition_20130115],
[dataset.partition_20130214])
WHERE created BETWEEN Timestamp('2013-01-05 00:00:00') AND Timestamp ('2013-02-15 23:59:59.999999')
AND id IN (
SELECT id
FROM [dataset.partition_20121216],
[dataset.partition_20130115],
[dataset.partition_20130214]
WHERE created BETWEEN Timestamp('2013-01-05 00:00:00') AND Timestamp ('2013-02-15 23:59:59.999999')
AND name = 'G’
)
GROUP each a
ORDER BY a
Upvotes: 4