CODEWITHSUNDEEP
scalasplit
Mehdi Erk
Mehdi Erk

Reputation: 31

Splitting String in scala ignores void fields at the end

I'm a scala beginer, and I'm facing this issue :

From : "abcd ; efgh ; ijkl ; ; ; ; "

I would like to have : Array["abcd ","efgh "," ijkl " , "", "" , "" ,""]

While the split function returns : ["abcd ","efgh "," ijkl " ]

Could Someone help please ?

Thanks in advance!

Upvotes: 0

Views: 85

Answers (1)

Lomig Mégard
Lomig Mégard

Reputation: 1828

This behaviour comes from the Java method split(regex). If you want to keep the trailing empty strings in your returned array you must use the overloaded method split(regex, limit):

scala> "a,b,c,,".split(",")
res0: Array[String] = Array(a, b, c)

scala> "a,b,c,,".split(",", -1)
res1: Array[String] = Array(a, b, c, "", "")

Note that the string given in your example actually works because you added spaces between the separators:

scala> "a , b , c , , ".split(",")
res2: Array[String] = Array("a ", " b ", " c ", " ", " ")

Upvotes: 3

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