CODEWITHSUNDEEP
iosobjective-c
Chris Holloway
Chris Holloway

Reputation: 247

iOS 8: handling data returned from iTunes Search API

I am using iTunes Search APIs to return the number of users that have reviewed my current app version. Since I haven't released the app yet, I have to handle the case where the iT search API returns nothing.

Here's the pertinent code:

 NSDictionary *iTunesDict = [NSJSONSerialization
 JSONObjectWithData:iTunesData options:0 error:&error];

 NSArray *resultCount = @[[iTunesDict valueForKey:@"resultCount"]];
 NSLog(@"%@", [resultCount objectAtIndex:0]);


       if ([resultCount objectAtIndex:0] == 0) {
           self.numberOfReviewers = @"0";

       } else {

         NSArray *reviewers = @[[[iTunesDict valueForKey:@"results"] valueForKey:@"userRatingCountForCurrentVersion"]];

         if ([reviewers objectAtIndex:0] == nil) {
         self.numberOfReviewers = @"0";

         } else {
           NSString *howManyReviewed = [[[reviewers objectAtIndex:0] objectAtIndex:0] stringValue];
           self.numberOfReviewers = howManyReviewed;
         }

My problem centers around the first if statement. Upon inspection, the value of...

[resultCount objectAtIndex:0] is: (__NSCFNumber *)(long)0

does not satisfy the condition in my first if.

What do I need to make a **(__NSCFNumber *)(long)0 **== 0??

Upvotes: 0

Views: 58

Answers (1)

John Rogers
John Rogers

Reputation: 2192

It's returning the data as an NSNumber object. Use the compare: comparison function:

if ([resultCount[0] compare:@0] == NSOrderedSame) {
    ...
}
else {
    ...
}

What this is doing is comparing the resultCount object to an NSNumber with the value of 0 (you can use the literal @0 to short-hand an NSNumber as I've done above). compare: returns one of three values:

  • NSOrderedDescending
  • NSOrderedSame
  • NSOrderedAscending

This reads from left to right. So if I was to use NSOrderedDescending, this would read logically "is 0 smaller than resultCount" (in descending order from left to right).

For further reading, check out the comparing NSNumber objects documentation.

Alternatively, because you know it's a long, you can use the longValue method on NSNumber:

if ([resultCount longValue] == 0) {
    ....
}

Upvotes: 2

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