Reputation: 9479
I have the following command I run in terminal:
mongoexport --db database_name --collection agents --type=csv --fieldFile agFieldsTest.txt --out file/path/agTestInfo.csv
I tried to run it using:
>>> import subprocess
>>> subprocess.call(["mongoexport --db database_name --collection agents --type=csv --fieldFile agFieldsTest.txt --out file/path/agTestInfo.csv"])
I get the following error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 524, in call
return Popen(*popenargs, **kwargs).wait()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 711, in __init__
errread, errwrite)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 1308, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
Upvotes: 1
Views: 108
Reputation: 992927
The best way is to break up the command into individual "words":
>>> subprocess.call(["mongoexport", "--db", "database_name", "--collection", "agents", "--type=csv", "--fieldFile", "agFieldsTest.txt", "--out", "file/path/agTestInfo.csv"])
Alternatively, you can use shell=True
to have the shell do that for you:
>>> subprocess.call(["mongoexport --db database_name --collection agents --type=csv --fieldFile agFieldsTest.txt --out file/path/agTestInfo.csv"], shell=True)
Upvotes: 2