Reputation: 1514
I am using the break statement and I want it to, when I enter 3, break and log "I am breaking."
But somehow it's not working.
Here is my code:
var enteredNumber=window.prompt("Enter A Value");
for (i=enteredNumber; i <= 10; i++) {
if (enteredNumber===3) {
console.log('I am breaking');
break;
}
}
It dosen't show any result. What am I doing wrong?
Upvotes: 0
Views: 75
Reputation: 2701
Basically you are using strict comparison so it wont accept 3 as number.
var enteredNumber=window.prompt("Enter A Value");
for (i=enteredNumber; i <= 10; i++) {
if (i==3) {
alert('i am breaking');
break;
}
Upvotes: 1
Reputation: 103155
This is a datatype problem. The value entered is a String and you are comparing it to a number. Try this:
var enteredNumber=+window.prompt("Enter A Value");
for (i=enteredNumber; i <= 10; i++) {
if (enteredNumber===3) {
console.log('i am Breaking');
break;
}
}
Notice the little + sign? That says to interpret the value entered as a number. Now the condition enteredNumber ===3
is true when you enter 3.
Upvotes: 3
Reputation: 1167
To stop the loop at 3
, your if statement should look at variable i
and not at enteredNumber
because you're looping i
and not enteredNumber
if (i===3) {
console.log('i am Breaking');
break;
}
Upvotes: 0