CODEWITHSUNDEEP
assemblymipsfile-read
Vikrant
Vikrant

Reputation: 101

Read binary file into array in MIPS

I've got a file named trace.dat that contains 4 byte integers. Can anybody tell me how to open and read the file, and store each integer in an array called arr (in MIPS)? Thanks!

So far I have this:

li $v0, 13
la $a0, file    #file contains the file name
li $a1, 0
li $a2, 0
syscall
add $s0, $v0, $0

Upvotes: 1

Views: 2462

Answers (1)

Daniel Kamil Kozar
Daniel Kamil Kozar

Reputation: 19286

The code you have merely opens the file, and does not read it. In order to actually read the contents of a file you've opened into a buffer, you need to use syscall number 14, like this :

li $v0, 14
move $a0, $s0
la $a1, arr
li $a2, 32
syscall
bltz $v0, error

This code assumes that $s0 contains the file descriptor of the opened file, which you already have in there due to add $s0, $v0, $0. It also assumes that the size of arr is 32 bytes.

If your file is larger than 32 bytes, you can write a loop that runs until syscall 14 returns 0 or a value smaller than the size of the buffer. Then, you can process the data read from the file inside the loop.

Upvotes: 3

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