Trim spaces from start and end of string

Question

I am trying to find a way to trim spaces from the start and end of the title string. I was using this, but it doesn't seem to be working:

title = title.replace(/(^[\s]+|[\s]+$)/g, '');

Any ideas?

Answer 1

You can use trimLeft() and trimRight() also.

const str1 = "   string   ";
console.log(str1.trimLeft()); 
// => "string   "

const str2 = "   string   ";
console.log(str2.trimRight());
// => "    string"

Answer 2

var word = " testWord ";   //add here word or space and test

var x = $.trim(word);

if(x.length > 0)
    alert('word');
else
    alert('spaces');

Answer 3

This is what is suggested by JavaScript Architect/Guru Douglas Crockford.

String.method('trim', function (  ) {
    return this.replace(/^\s+|\s+$/g, '');
});

Note: you have to define "method" for Function.prototype.

Alternatively

String.prototype.trim = function () {
   return this.replace(/^\s+|\s+$/g, '');
};

title.trim();    // returns trimmed title

Observation

In recent browsers, the trim method is included by default. So you don't have to add it explicitly.

Major browsers Chrome, Firefox, Safari etc. supports trim method. Checked in Chrome 55.0.2883.95 (64-bit), Firefox 51.0.1 (64-bit), Safari 10.0 (12602.1.50.0.10).

Answer 4

a recursive try for this

function t(k){ 
    if (k[0]==' ') {
        return t(k.substr(1,k.length));
    } else if (k[k.length-1]==' ') {
        return t(k.substr(0,k.length-1));
    } else {
        return k;
    }
}

call like this:

t("      mehmet       "); //=>"mehmet"

if you want to filter spesific chars you can define a list string basically:

function t(k){
    var l="\r\n\t "; //you can add more chars here.
    if (l.indexOf(k[0])>-1) {
        return t(k.substr(1,k.length));
    } else if (l.indexOf(k[k.length-1])>-1) {
        return t(k.substr(0,k.length-1));
    } else {
        return k;
    }
}

Answer 5

Note: As of 2015, all major browsers (including IE>=9) support String.prototype.trim(). This means that for most use cases simply doing str.trim() is the best way of achieving what the question asks.

---

Steven Levithan analyzed many different implementation of trim in Javascript in terms of performance.

His recommendation is:

function trim1 (str) {
    return str.replace(/^\s\s*/, '').replace(/\s\s*$/, '');
}

for "general-purpose implementation which is fast cross-browser", and

function trim11 (str) {
    str = str.replace(/^\s+/, '');
    for (var i = str.length - 1; i >= 0; i--) {
        if (/\S/.test(str.charAt(i))) {
            str = str.substring(0, i + 1);
            break;
        }
    }
    return str;
}

"if you want to handle long strings exceptionally fast in all browsers".

References

• blog.stevenlevithan.com -- Faster JavaScript Trim

Answer 6

I know this is an old post, but just thought I'd share our solution. In the quest for shortest code (doesn't everyone just love terse regex), one could instead use:

title = title.replace(/(^\s+|\s+$)/g, '');

BTW: I ran this same test through the link shared above blog.stevenlevithan.com -- Faster JavaScript Trim and this pattern beat all the other HANDS down!

Using IE8, added test as test13. The results were:

Original length: 226002
trim1: 110ms (length: 225994)
trim2: 79ms (length: 225994)
trim3: 172ms (length: 225994)
trim4: 203ms (length:225994)
trim5: 172ms (length: 225994)
trim6: 312ms (length: 225994)
trim7: 203ms (length: 225994)
trim8: 47ms (length: 225994)
trim9: 453ms (length: 225994)
trim10: 15ms (length: 225994)
trim11: 16ms (length: 225994)
trim12: 31ms (length: 225994)
trim13: 0ms (length: 226002)

Answer 7

When the DOM is fully loaded, you can add this to all the text fields. I have never had a situation where I needed to submit leading or trailing space, so doing it all the time globally has worked for me...

$(function() { $('input[type=text]').on('blur', function(){
    $(this).val($.trim($(this).val()));
  });
});

Answer 8

Just use string.trim() method. It's supported by all major browsers. Reference here: http://www.w3schools.com/jsref/jsref_trim_string.asp

Answer 9

jQuery.trim(" hello, how are you? ");

:)

Answer 10

If using jQuery is an option:

/**
 * Trim the site input[type=text] fields globally by removing any whitespace from the
 * beginning and end of a string on input .blur()
 */
$('input[type=text]').blur(function(){
    $(this).val($.trim($(this).val()));
});

or simply:

$.trim(string);

Answer 11

Here, this should do all that you need

function doSomething(input) {
    return input
              .replace(/^\s\s*/, '')     // Remove Preceding white space
              .replace(/\s\s*$/, '')     // Remove Trailing white space
              .replace(/([\s]+)/g, '-'); // Replace remaining white space with dashes
}

alert(doSomething("  something with  some       whitespace   "));

Answer 12

As @ChaosPandion mentioned, the String.prototype.trim method has been introduced into the ECMAScript 5th Edition Specification, some implementations already include this method, so the best way is to detect the native implementation and declare it only if it's not available:

if (typeof String.prototype.trim != 'function') { // detect native implementation
  String.prototype.trim = function () {
    return this.replace(/^\s+/, '').replace(/\s+$/, '');
  };
}

Then you can simply:

title = title.trim();

Answer 13

Here is my current code, the 2nd line works if I comment the 3rd line, but don't work if I leave it how it is.

var page_title = $(this).val().replace(/[^a-zA-Z0-9\s]/g, '');
page_title = page_title.replace(/^\s\s*/, '').replace(/\s\s*$/, '');
page_title = page_title.replace(/([\s]+)/g, '-');

Answer 14

ECMAScript 5 supports trim and this has been implemented in Firefox.

trim - MDC

Answer 15

Here is some methods I've been used in the past to trim strings in js:

String.prototype.ltrim = function( chars ) {
    chars = chars || "\\s*";
    return this.replace( new RegExp("^[" + chars + "]+", "g"), "" );
}

String.prototype.rtrim = function( chars ) {
    chars = chars || "\\s*";
    return this.replace( new RegExp("[" + chars + "]+$", "g"), "" );
}
String.prototype.trim = function( chars ) {
    return this.rtrim(chars).ltrim(chars);
}