Reputation: 141
I looked now through a various number of StackOverflow pages and other websites - but can't find the correct solution for my problem. I try to post two values over to a php page via Post:
loginframe.php:
<form class="signin">
<input type="username" id="inputUsername" class="control" placeholder="Username" required autofocus>
<input type="password" id="inputPassword" class="control" placeholder="Password" required>
<div id="remember" class="checkbox">
<label>
<input type="checkbox" value="remember-me">Remember me
</label>
</div>
<button class="btn-login" type="submit" value="login" id="btn-login">Sign in</button>
</form>
My js:
$(document).ready(function(){
$("#btn-login").click(function(){
var username = $("#inputUsername").val();
var password = $("#inputPassword").val();
$.ajax(
{
type: "POST",
url: 'login.php',
data: {
user: username,
pass: password
},
success: function(result)
{
$("#result").html(result);
}
});
});
});
My login.php
<?php
if(isset($_POST['user']) && isset($_POST['pass']))
{
echo $_POST['user'];
echo $_POST['pass'];
} else {
include 'loginframe.php';
}
This login.php is just to check now if the data is passed. That is absolutely not the case. It always opens loginframe.php... I can't find the error - I appreciate your help! Thank you a lot.
Upvotes: 0
Views: 58
Reputation: 3827
Use prevent default method.
$(document).ready(function(){
$("#btn-login").click(function(event){
event.preventDefault(); // this one prevents the default submission of the form
var username = $("#inputUsername").val();
var password = $("#inputPassword").val();
$.ajax(
{
type: "POST",
url: 'login.php',
data: {
user: username,
pass: password
},
success: function(result)
{
$("#result").html(result);
}
});
});
});
Upvotes: 2