CODEWITHSUNDEEP
python
boxxybabee
boxxybabee

Reputation: 55

Check a line value in python from a file

So I have this .txt file that has over 100 lines and a value on each one.
How would I read the value from a specific line and use it in an if?
Let's say I want to read the line 34 and see if the line has the value 0 or 1 in it. I don't really know how to explain but i was thinking about something like this. would I be able to assign "print(lines[34])" an integer and then compare the integer with 0 or 1? please keep in mind that i have no experience with python. 

f = open("NT.txt",'r')
lines = f.readlines()
if print(lines[34]) == 1:
    print("something")

Upvotes: 1

Views: 1570

Answers (3)

Deacon
Deacon

Reputation: 3813

As @JoranBeasley pointed out to my solution in the comment up there, anything read in from a text file is read in as...text (duh!). It would need to be converted to an int, so the proper if statement should be:

if int(lines[34].strip()) == 1:
    # Do something here.

Additionally, most folks would probably open the text file using a with statement, so that it closes automagically when you're done using it:

with open('NT.txt', 'r') as f:
    lines = f.readlines()
if int(lines[34].strip()) == 1:
    # Do something here.

Upvotes: 1

RTB
RTB

Reputation: 86

This should work:

f=open('NT.txt', 'r')
lines=f.readlines()

if int(lines[34])==1:
    print('something')

Upvotes: 0

Joran Beasley
Joran Beasley

Reputation: 114108

if lines[34].strip() == "1":

since files are always text ... might answer your question?

(note that since lists start with 0 lines[34] is the 35th line)

of coarse someone may have told you to try

if int(lines[34])==1:

and you heard print instead of int

Upvotes: 2

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