Reputation: 4815
I have written following query to get the count and percentage value for individual user:
select a.user_type,a.count,a.count * 100/(select sum(sessions) from user_type) as percentage
from
(select user_type, sum(sessions) as count
from user_type
group by user_type
order by user_type) a,
(select user_type, sum(sessions) as count
from user_type
group by user_type
order by user_type) b
where a.user_type = b.user_type and a.count = b.count
group by a.user_type,a.count
The percentage values are coming like 7.35684648. Can someone tell me what changes shall I do to get the % value as per my requirement.
Upvotes: 2
Views: 7075
Reputation: 2091
You can use the round function.
select a.user_type,a.count,round(a.count * 100/(select sum(sessions) from user_type),2) ...
This should truncate the percentage value to 2 decimal places.
Upvotes: 3