CODEWITHSUNDEEP
pythonocrpytesser
TyLo
TyLo

Reputation: 19

pytesser subprocess.Popen fail

since yesterday im trying to use the OCR pytesser. I solved few problems by myself but i c'ant figure out how to get ride of this one. there is the error :

H:\Python27>python.exe lol.py
Traceback (most recent call last):
File "lol.py", line 30, in <module>
print image_to_string(image)
File "H:\Python27\lib\pytesser\__init__.py", line 30, in image_to_string
call_tesseract(scratch_image_name, scratch_text_name_root)
File "H:\Python27\lib\pytesser\__init__.py", line 20, in call_tesseract
proc = subprocess.Popen(args)
File "H:\Python27\lib\subprocess.py", line 710, in __init__
errread, errwrite)
File "H:\Python27\lib\subprocess.py", line 958, in _execute_child
 startupinfo)
WindowsError: [Error 2] Le fichier spÚcifiÚ est introuvable

the last line say "the file cant be found"

there is how i put the tesseract in my init.py

tesseract_exe_name = 'C:\Users\TyLo\AppData\Local\Tesseract-OCR\tesseract' # Name of executable to be called at command line

i really cant figure out why he cant open the file. there is 2 other things also, in my init.py. I can change the image file and the txt file i tried to create mine and give him the path no sucess, but i think he create them himself.

scratch_image_name = "outfile.bmp" # This file must be .bmp or other Tesseract-compatible format
scratch_text_name_root = "infile" # Leave out the .txt extension

this is the 3 files that are sent to Popen so i imagine the error is there.

I hope im clear enough for you guys to understand the problem i have.

edit: the in lol.py is from this site, just modified the url http://www.debasish.in/2012/01/bypass-captcha-using-python-and.html

Upvotes: 0

Views: 1195

Answers (1)

abarnert
abarnert

Reputation: 366003

This is the problem:

tesseract_exe_name = 'C:\Users\TyLo\AppData\Local\Tesseract-OCR\tesseract' # Name of executable to be called at command line

See the \t there? That's a single tab character, not a backslash character and a t character. And you only get away with \U, \T, \A, \L, and \T because you got lucky and nobody had thought of a use for them yet by the time your version of Python came out. (Later versions of Python do actually have a use for \U.)

The solution is to do one of the following:

(1) Use a raw string literal

tesseract_exe_name = r'C:\Users\TyLo\AppData\Local\Tesseract-OCR\tesseract' # Name of executable to be called at command line

The r'…' means "don't treat backslashes specially".

(2) Escape all of your backslashes:

tesseract_exe_name = 'C:\\Users\\TyLo\\AppData\\Local\\Tesseract-OCR\\tesseract' # Name of executable to be called at command line

In a non-raw string literal, \\ means a single backslash, so \\t means a single backslash and a t.

(3) Use forward slashes instead:

tesseract_exe_name = 'C:/Users/TyLo/AppData/Local/Tesseract-OCR/tesseract' # Name of executable to be called at command line

Most Windows programs accept forward slashes. A few don't, and occasionally you need a \\.\ pathname that isn't legal with forward slashes, but otherwise, this works.

Upvotes: 3

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