CODEWITHSUNDEEP
regexbashsedcentos
Marc
Marc

Reputation: 3

How to extract a complex version number using sed?

I use sed in CentOs to extract version number and it's work fine:

echo "var/opt/test/war/test-webapp-4.1.56.war" | sed -nre 's/^[^0-9]*(([0-9]+\.)*[0-9]+).*/\1/p'

But my problem is that i am not able to extract when the version is shown like this:

var/opt/test/war/test-webapp-4.1.56-RC1.war

I want to extract the 4.1.56-RC1 if it is present.

Any ideas ?

EDIT 2

Ok to be clear take this example, with a path:

Sometimes the path contains only a serial number like this var/opt/test/war/test-webapp-4.1.56.war and sometimes it contains a series of numbers and letters like this "var/opt/test/war/test-webapp-4.1.56-RC1.war

The need is to recover either 4.1.56 or 4.1.56-RC1 depending on the version present in the path. With sed or grep, no preference.

This seems to work but the .war is shown at the end:

echo "var/opt/test/war/test-webapp-4.1.56.war" | egrep -o '[0-9]\S*'

Upvotes: 0

Views: 418

Answers (6)

user4401178
user4401178

Reputation:

The following will match the first digit up to 2 digits in length ({1,2}, second up to 2 digits and the last up to 4 digits followed by anything non-space up to a space. 

grep -o '[0-9]\{1,2\}.[0-9]\{1,2\}.[0-9]\{1,4\}'

Upvotes: 1

NeronLeVelu
NeronLeVelu

Reputation: 10039

echo "Version 4.2.4 (test version)" | sed 's/Version[[:space:]]*\([^[:space:](]*\).*/\1/'

But like every extraction, you need to define what you want, not what could exist and extract it (or change your request).

Upvotes: 0

Vytenis Bivainis
Vytenis Bivainis

Reputation: 2376

This passes both tests

egrep -o '[0-9]\S*'

Unfortunately, not all greps support -o, but grep in Linux does.

Upvotes: 0

dawg
dawg

Reputation: 103694

Little unclear what you are after, but this seems to be in the general direction.

Given:

$ echo "$e"
/var/opt/test/war/test-webapp-4.1.56-RC1.war
/var/opt/test/war/test-webapp-RC1.war
Version 4.2.4 (test version)

Try:

$ echo "$e" | egrep -o '(\d+\.\d+\.\d+-?\w*)'
4.1.56-RC1
4.2.4

Upvotes: 1

karthik manchala
karthik manchala

Reputation: 13640

Just add (-[a-zA-Z]+[0-9]+) to your regex:

echo "Version 4.2.4 (test version)" | sed -nre 's/^[^0-9]*(([0-9]+\.)*[0-9]+(-[a-zA-Z]+[0-9]+)).*/\1/p'

Upvotes: 0

Eric Renouf
Eric Renouf

Reputation: 14490

What about just using whitespace as the delimiter like

echo "Version 4.2.4-RC1 (test version)" | grep -Po "Version\s+\K\S+"

for grep -P says to use Perl style regex, -o shows only the matching part and the \K in the string says not to show everything before it as part of the match

Upvotes: 0

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