CODEWITHSUNDEEP
c++arraysexception
Sree
Sree

Reputation: 347

C++ Exception:Throwing Arrays and getting array size in catch

A Normal function ( say printArray) takes array and its size ( 2 arguments ) to print elements of an array.

How to do the same using exceptions? More exactly, how to pass array size to catch handler ? ( assuming I dont have a const int SIZE declared outside try-catch) eg.

 //void printArray(int* foo ,int size);
     int foo[] = { 16, 2, 77, 40, 12071 };
   //printArray(foo,5); //OK, function call using array accepts size=5 
    try{

        //do something
        throw foo;

    }
    catch (int* pa)
    {
        //I have to get array size to loop through and print array values
        //    How to get array size?
    }

Thank you in advance

Upvotes: 5

Views: 3176

Answers (2)

Sree
Sree

Reputation: 347

Thank you all for the comments. pair example works ( probably will use when using arr on heap, and when thrown , caught on calling function ). celtschk ref, was very helpful . I will use this info for local non static array on same scope 

int main()
{
    int foo[] = { 16, 2, 77, 40, 12071 };
    int size = sizeof(foo)/ sizeof(int);
    try{
        //throw foo;
        throw (pair<int*,int>(foo,size));
    }
    catch (int* foo)
    {
        for (int i = 0; i < size; i++)
            cout << foo[i] << ",";
    }
    catch (pair<int*, int>& ip)
    {
        cout << "pair.." << endl;
        for (int i = 0; i < ip.second; i++)
            cout << ip.first[i] << ",";
    }
    cout << endl;
}

Upvotes: 0

Mohammad Shokri
Mohammad Shokri

Reputation: 417

You can throw both array and it's size as a pair in the following way:

throw std::make_pair(foo, 5);

and get these two values like this:

catch(std::pair<int*, int>& ex)
{
...
}

Upvotes: 6

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