CODEWITHSUNDEEP
ruby-on-railshash
user3931577
user3931577

Reputation: 43

Grouping hash by value and get count of the values under one group in Rails

I have a code that gets the list of checkins given a span of time. See code below.

from = Time.zone.now.beginning_of_month
to   = Time.zone.now.end_of_month
customer_checkins = CustomerCheckin.where(account_id: seld.id, created_at: from..to)

The code would then give me all checkin objects that satisfies the given condition. The next thing that I need to do is to group the list of checkins per customer. So I have this code to do that.

group_customer_id = customer_checkins.group(:customer_id).count

Grouping it by customer id will then result to a hash. See example below.

{174621=>9,180262=>1,180263=>1,180272=>1,180273=>3,180274=>3,180275=>4,180276=>3,180277=>2,180278=>4,180279=>4,180280=>3,180281=>5,180282=>8}

I would like now to get the count of customers with the same checkin count - how many customers have 9 checkins, 5 checkins, etc. So given the hash above. I am expecting an output like this:

{9 => 1, 8=> 1, 5 => 1, 4=> 3, 3 => 4, 2=> 1, 1 => 3}

Upvotes: 1

Views: 348

Answers (3)

rick
rick

Reputation: 1705

a = {174621=>9,180262=>1,180263=>1,180272=>1,180273=>3,180274=>3,180275=>4,180276=>3,180277=>2,180278=>4,180279=>4,180280=>3,180281=>5,180282=>8}

result = a.map{|k,v| v}.each_with_object(Hash.new(0)) { |word,counts| counts[word] += 1 }

# => {9=>1, 1=>3, 3=>4, 4=>3, 2=>1, 5=>1, 8=>1}

Upvotes: 0

Abhi
Abhi

Reputation: 4271

Get the values from hash like:

customer_array = {174621=>9,180262=>1,180263=>1,180272=>1,180273=>3,180274=>3,180275=>4,180276=>3,180277=>2,180278=>4,180279=>4,180280=>3,180281=>5,180282=>8}.values
customer_count = Hash.new(0)

customer_array.each do |v|
  customer_count[v] += 1
end

puts customer_count

Upvotes: 0

Santhosh
Santhosh

Reputation: 29174

h.each_with_object({}) {|(k,v), h| h[v] = h[v].to_i + 1}
# => {9=>1, 1=>3, 3=>4, 4=>3, 2=>1, 5=>1, 8=>1}

Upvotes: 1

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