Reputation: 12675
I'm trying to make a table, and the way Pandas formats its indices is exactly what I'm looking for. That said, I don't want the actual data, and I can't figure out how to get Pandas to print out just the indices without the corresponding data.
Upvotes: 48
Views: 278810
Reputation: 453
You can always try df.index
. This function will show you the range index.
Or you can always set your index. Let say you had a weather.csv file with headers: 'date', 'temperature' and 'event'. And you want set "date" as your index.
import pandas as pd
df = pd.read_csvte'weather_file)
df.set_index('day', inplace=True)
df
Upvotes: 0
Reputation: 11
You can use lamba function:
index = df.index[lambda x : for x in df.index() ]
print(index)
Upvotes: 1
Reputation: 432
You can access the index attribute of a df using df.index[i]
>> import pandas as pd
>> import numpy as np
>> df = pd.DataFrame({'a':np.arange(5), 'b':np.random.randn(5)})
a b
0 0 1.088998
1 1 -1.381735
2 2 0.035058
3 3 -2.273023
4 4 1.345342
>> df.index[1] ## Second index
>> df.index[-1] ## Last index
>> for i in xrange(len(df)):print df.index[i] ## Using loop
...
0
1
2
3
4
Upvotes: 11
Reputation: 16154
.index.tolist()
is another function which you can get the index as a list:
In [1391]: datasheet.head(20).index.tolist()
Out[1391]: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
Upvotes: 32
Reputation: 394129
You can access the index attribute of a df using .index
:
In [277]:
df = pd.DataFrame({'a':np.arange(10), 'b':np.random.randn(10)})
df
Out[277]:
a b
0 0 0.293422
1 1 -1.631018
2 2 0.065344
3 3 -0.417926
4 4 1.925325
5 5 0.167545
6 6 -0.988941
7 7 -0.277446
8 8 1.426912
9 9 -0.114189
In [278]:
df.index
Out[278]:
Int64Index([0, 1, 2, 3, 4, 5, 6, 7, 8, 9], dtype='int64')
Upvotes: 66