Reputation: 5131
I have tested this in two applications; Where I pass in a char looking for a special character.
static void Main(string[] args)
{
ConsoleKeyInfo entered = Console.ReadKey();
char asChar = Convert.ToChar(entered.KeyChar);
Console.WriteLine(IsSpecialChar(asChar));
Console.ReadKey();
}
private static string IsSpecialChar(char dWord)
{
List<char> Special = new List<char>();
System.Globalization.NumberStyles hexer = System.Globalization.NumberStyles.HexNumber;
Special.AddRange(Enumerable.Range((int.Parse("21", hexer)), int.Parse("2f", hexer)).Select(x => Convert.ToChar(x)));
Special.AddRange(Enumerable.Range((int.Parse("3a", hexer)), int.Parse("40", hexer)).Select(x => Convert.ToChar(x)));
Special.AddRange(Enumerable.Range((int.Parse("5c", hexer)), int.Parse("60", hexer)).Select(x => Convert.ToChar(x)));
Special.AddRange(Enumerable.Range((int.Parse("7e", hexer)), int.Parse("7e", hexer)).Select(x => Convert.ToChar(x)));
if (Special.Contains(Convert.ToChar(dWord)))
{
return "Special";
}
else return "NA";
}
For some reason the Special.Contains always sees the opposite of what is true.
Some of the characters that are populated are:
U+003F ? 3f QUESTION MARK
U+0040 @ 40 COMMERCIAL AT
U+0041 A 41 LATIN CAPITAL LETTER A
U+0042 B 42 LATIN CAPITAL LETTER B
Letters A and B should not be there. What is going on?
Upvotes: 0
Views: 79
Reputation: 203811
Enumerable.Range accepts a start of the range and the length of the range rather than a start of the range and an end of the range.
Because of this, your ranges aren't at all what you intended them to be.
Upvotes: 7